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iren2701 [21]
4 years ago
7

Given a wind turbine with blades that sweep out a 10 m diameter circle, and a wind speed of 2 m/s, approximately what is the max

imum possible power that the turbine can produce (i.e. taking into account the Betz limit)? Assume that the density of air is 1.2 kg/m3. Group of answer choices
Physics
1 answer:
Mars2501 [29]4 years ago
8 0

Answer:

223.55 W

Explanation:

v = Velocity of wind = 10 m/s

r = Radius of circle = 5 m

S = Swept area

\rho = Density of air = 1.2 kg/m³

C_p = Power coefficient = 0.593

P=C_p\frac {1}{2}}\rho Sv^{3}\\\Rightarrow P=0.593\times \frac{1}{2}1.2 \pi \times 5^2\times 2^{3}\\\Rightarrow P=223.55\ W

The maximum possible power that can be produced by the turbine is 223.55 W

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Gold has a density of 19300 kg/m³. Calculate the mass of 0.02 m³ of gold in kilograms.
hjlf

Answer:

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Lelechka [254]

In order to determine the required force to stop the car, proceed as follow:

Calculate the deceleration of the car, by using the following formula:

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Solve the equation above for a, replace the values of the other parameters and simplify:

\begin{gathered} a=\frac{v^2_o-v^2}{2x} \\ a=\frac{(36\frac{m}{s})^2-(0\frac{m}{s})^2}{2(980m)}=0.66\frac{m}{s^2} \end{gathered}

Next, consider that the formula for the force is:

F=ma

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Replace the previous values and simplify:

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