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3 years ago

Entropy can be thought of as the degree of disorganization of a system. TRUE FALSE

Chemistry

1 answer:

Mice21 [21]3 years ago

7 0

Answer:

True

Explanation:

The entropy of a system denoted by S is a thermodynamic function that increases in value when there are more ways to arrange the particles in the system. Some spontaneous chemical processes are entropy driven. An increase in entropy is said to drive the dissolution of ionic salts along with the evaporation of water are related to the spreading out of energy.

The entropy of a system can be taken as a measure of disorder of a system. In a spontaneous chemical process, the entropy of the universe is said to increase. ΔSunivu>0. Making the answer true.

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A + B ->C<br><br><br>Which situation best describes the effect of a limiting reactant?

anygoal [31]

Answer:

The Limiting Reactant is the reactant that when consumed the reaction stops.

Explanation:

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3 years ago

Which phrase best defines a chemical bond?

Mice21 [21]

Answer:

Chemical bond can be define as a force holding atoms firmly together to a form molecules.

Explanation:

Chemical bond is a strong attraction between atoms, molecules or ions that enhance the formation of chemical compounds. The bonds may be due from the electrostatic force of attraction between opposite charged ions or through the sharing of electrons.

Types of chemical bond

There are four types of chemical bonds

- covalent bond

- polar bond

- ionic bond

- hydrogen bond

Ionic bond involves the transfer of an electron which involves one atom receiving and the other giving out

Covalent bond involves the sharing of electrons between two atoms

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3 years ago

OxYgen and hydrogen particles are kept in a container. Which of the following

Tema [17]

Answer:

Option D

Oxygen particles mix evenly with hydrogen particles.

Explanation:

Diffusion refers to the movement of gasses from a region of higher concentration to a region of lower concentration.

Diffusion occurs in gases because their particles are in a state of constant random motion.

Due to this continuous random motion, once the oxygen and the hydrogen are added to the container, they will begin to mix freely with each other until they fill up the entire volume of the container.

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3 years ago

Which bottle held the most water?

bogdanovich [222]

Bottle 4. That or bottle 3 because they BOTH hold 900 grams, which is bigger than 600 or 800

3 0

3 years ago

1) 0.5 moles of sodium chloride is dissolved to make 0.05 liters of solution. 2) 734 grams of lithium sulfate are dissolved to m

OLEGan [10]

Answer:

1)Molarity of 0.5 Moles of Sodium Chloride in 0.05 Liters of solution is 10 M.

2)Molarity of 734 grams of lithium sulfate are dissolved to make 2500 mL of solution is 2.68 M.

3)Molarity of a solution is made by adding 83 grams of sodium hydroxide to 750 mL of water is 2.77 M.

4)Molarity of a solution that contains .500 mol HC₂H₃O₂ in 0.125 kg H₂O is 4 M.

5)Molarity of a solution that contains 63.0 g HNO₃ in 0.500 kg H₂O is 2 M.

6)The mass of water required to form 3.0 M solution by dissolving 0.5kg of C₂H₅OH is 3.62 kg.

Explanation:

Molarity is given as

$M=\dfrac{n}{V}$

Here

n is number of moles
V is the volume of the solution in liters

Using this all the values are calculated as follows:

1)Molarity of 0.5 Moles of Sodium Chloride in 0.05 Liters of solution is

$M=\dfrac{n}{V}\\M=\dfrac{0.5}{0.05}\\M=10$

So the molarity is 10 M.

2)Molarity of 734 grams of lithium sulfate are dissolved to make 2500 mL of solution is

$M=\dfrac{n}{V}$

Here n is calculated as follows:

$n=\dfrac{mass\ of\ solute}{Molar\ mass\ of\ Solute}$

Here the molar mass of lithium sulphate is as follows:

$MM of Li_2SO_4=2\times Li+S+4\times O\\MM of Li_2SO_4=2\times 7+32+4\times 16\\MM of Li_2SO_4=110$

So n is

$n=\dfrac{mass\ of\ solute}{Molar\ mass\ of\ Solute}\\n=\dfrac{734}{110}\\n=6.67$

V is given as

$V_{L}=\dfrac{V_{mL}}{1000}\\V_{L}=\dfrac{2500}{1000}\\V_{L}=2.5\ L$

So the molarity is given as

$M=\dfrac{n}{V}\\M=\dfrac{6.67}{2.5}\\M=2.68\ M$

So the molarity is 2.68 M.

3)Molarity of a solution is made by adding 83 grams of sodium hydroxide to 750 mL of water is

$M=\dfrac{n}{V}$

Here n is calculated as follows:

$n=\dfrac{mass\ of\ solute}{Molar\ mass\ of\ Solute}$

Here the molar mass of Sodium hydroxide is as follows:

$MM of NaOH=Na+O+H\\MM of NaOH=23+16+1\\MM of NaOH=40$

So n is

$n=\dfrac{mass\ of\ solute}{Molar\ mass\ of\ Solute}\\n=\dfrac{83}{40}\\n=2.075$

V is given as

$V_{L}=\dfrac{V_{mL}}{1000}\\V_{L}=\dfrac{750}{1000}\\V_{L}=0.75\ L$

So the molarity is given as

$M=\dfrac{n}{V}\\M=\dfrac{2.075}{0.75}\\M=2.77\ M$

So the molarity is 2.77 M.

4)Molarity of a solution that contains .500 mol HC₂H₃O₂ in 0.125 kg H₂O is

$M=\dfrac{n}{V}$

V is given as

$V_{L}=\dfrac{mass}{density}\\V_{L}=\dfrac{0.125}{1 kg/L}\\V_{L}=0.125\ L$

So the molarity is given as

$M=\dfrac{n}{V}\\M=\dfrac{0.5}{0.125}\\M=4.0\ M$

So the molarity is 4.00 M.

5)Molarity of a solution that contains 63.0 g HNO₃ in 0.500 kg H₂O is

$M=\dfrac{n}{V}$

Here n is calculated as follows:

$n=\dfrac{mass\ of\ solute}{Molar\ mass\ of\ Solute}$

Here the molar mass of HNO₃ is as follows:

$MM of HNO_3=H+N+3\times O\\MM of HNO_3=1+14+3\times 16\\MM of HNO_3=63$

So n is

$n=\dfrac{mass\ of\ solute}{Molar\ mass\ of\ Solute}\\n=\dfrac{63}{63}\\n=1.00$

V is given as

$V_{L}=\dfrac{mass}{density}\\V_{L}=\dfrac{0.5}{1 kg/L}\\V_{L}=0.5\ L$

So the molarity is given as

$M=\dfrac{n}{V}\\M=\dfrac{1}{0.5}\\M=2.00\ M$

So the molarity is 2.00 M.

6)Mass of water must be used to dissolve 0.500 kg C₂H₅OH to prepare a 3.00 m solution is calculated as follows

$M=\dfrac{n}{V}$

Here n is calculated as follows:

$n=\dfrac{mass\ of\ solute}{Molar\ mass\ of\ Solute}$

Here the molar mass of C₂H₅OH is as follows:

$MM of C_2H_5OH=2\times C+6\times H+O\\MM of C_2H_5OH=2\times 12+6\times 1+16\\MM of C_2H_5OH=46$

So n is

$n=\dfrac{mass\ of\ solute}{Molar\ mass\ of\ Solute}\\n=\dfrac{500}{46}\\n=10.87$

V required is given as

$M=\dfrac{n}{V}\\V=\dfrac{n}{M}\\V=\dfrac{10.87}{3}\\V=3.62\ L$

So the mass of water is given as

$mass=density\times Volume\\mass=1 kg/L \times 3.62 L\\mass=3.62\ kg$

So the mass of water required to form 3.0 M solution by dissolving 0.5kg of C₂H₅OH is 3.62 kg.

6 0

3 years ago