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alexdok [17]
3 years ago
11

Entropy can be thought of as the degree of disorganization of a system. TRUE FALSE

Chemistry
1 answer:
Mice21 [21]3 years ago
7 0

Answer:

True

Explanation:

The entropy of a system denoted by S is a thermodynamic function that increases in value when there are more ways to arrange the particles in the system. Some spontaneous chemical processes are entropy driven. An increase in entropy is said to drive the dissolution of ionic salts along with the evaporation of water are related to the spreading out of energy.

The entropy of a system can be taken as a measure of disorder of a system. In a spontaneous chemical process, the entropy of the universe is said to increase. ΔSunivu>0. Making the answer true.

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Which of the following is an example of maintaining homeostasis? A. Learning B. Jumping C. Shivering D. Smiling
yawa3891 [41]

Answer:

Shivering.

Explanation:

Homeostasis is the bodies need to keep things at a normal. When you are cold you shiver to produce body heat and get back to normal  

5 0
3 years ago
The lone pair of electrons in ammonia allows the molecule to: A.assume a planar structure. B.act as an oxidizing agent. C.act as
serious [3.7K]

Answer:

The correct option is: D.act as a Lewis base in water.

Explanation:    

Ammonia is a hydride of nitrogen with the chemical formula NH₃. It is a colorless gas with a characteristic pungent smell. According to the VSEPR theory, it has a trigonal pyramidal structure.  

In water, ammonia acts as a Lewis base due to the presence of lone pair on the nitrogen atom. Lewis bases are electron pair or lone pair donors.      

8 0
3 years ago
Fundamental differences in the cell, the basic unit of life, allow for broadest classification of all living organisms into thre
Nana76 [90]

Answer:

C

Explanation:

7 0
3 years ago
What volume of 0.4567 m h2so4 is required to neutralize 30.00 ml of 0.3210 m naoh?
sertanlavr [38]
Answer is: volume of H₂SO₄ is 42.1 mL.<span>
Chemical reaction: H</span>₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.<span>
c(H</span>₂SO₄) = 0,4567 M = 0,4567 mol/L.<span>
V(NaOH) = 30 mL </span>÷ 1000 mL/L <span>= 0,03 L.
c(NaOH) = 0,321 M = 0,321 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,321 mol/L · 0,030 L.
n(NaOH) = 0,00963 mol.
From chemical reaction: n(H</span>₂SO₄) : n(NaOH) = 1 : 2.<span>
n(H</span>₂SO₄) = 0,01926 mol.<span>
V(H</span>₂SO₄) = n(H₂SO₄) ÷ c(H₂SO₄).<span>
V(H</span>₂SO₄) = 0,01926 mol ÷ 0,4567 mol/L.<span>
V(H</span>₂SO₄<span>) = 0,0421 L = 42,1 mL.</span>
3 0
3 years ago
a strip of impure copper is given to you. how will you purify it by using chemical effects of electric current ?
Oksi-84 [34.3K]

This can be done through electrolysis. Electrolysis is the separation of a substance  into two or more substances that may differ from each other and from the original substance by passing an electric current through a solution that contains ions.

In the case of copper,  we use a  copper (II) sulphate  solution which we put in a large beaker. The impure copper will be used as the positive electrode (anode) and for the negative electrode (cathode)  will be a bar of pure copper.

When the electric current is switched on, the bar of pure copper which is the cathode  increases greatly in size as copper ions leave the anode of impure copper and attach to  the cathode.  The anode becomes smaller and smaller as it loses copper ions until all that is left of it is impurities in form of a sludge beneath it.


6 0
3 years ago
Read 2 more answers
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