Answer:
H = 0.673
Explanation:
given,
side of cubical crate = 0.74
weight of the crate = 600 N
magnitude of force = 330 N
the Horizontal distance of its Center of mass
= 0.74/2
= 0.37
Let the required Height be H
By Balancing the Torques, we get
H x 330 N = 0.37 x 600
330 H = 222
H = 0.673
hence, the height above the floor where force is acting is equal to 0.673 m
I think the table can be called sandy because its like salt .
hope this help you out
good luck
Answer:
99.63 kg
Explanation:
From the force diagram
N = normal force on the worker from the surface of the roof
f = static frictional force = 560 N
θ = angle of the slope = 35
m = mass of the worker
W = weight of the worker = mg
W Cosθ = Component of the weight of worker perpendicular to the surface of roof
W Sinθ = Component of the weight of worker parallel to the surface of roof
From the force diagram, for the worker not to slip, force equation must be
W Sinθ = f
mg Sinθ = f
m (9.8) Sin35 = 560
m = 99.63 kg
Answer:
x=±0.026m
Explanation:
In simple harmonic motion the maximum value of the magnitude of velocity
The speed as a function of position for simple harmonic oscillator is given by
where A is amplitude of motion
Given data
Amplitude A=3 cm =0.03 m
v=(1/2)Vmax
To find
We have asked to find position x does its speed equal half of is maximum speed
Solution
The speed of the particle the maximum speed as:
x=±(√3(0.03)/2)
x=±0.026m
<em>If the distance between the two objects is the same, then;</em>
Both the magnet and the coil moving toward each other at 10 cm/s each
A reversed polarity magnet moving away from the coil at 20 cm/s
<u>Calculate current that produces a magnetic field, and use the right hand rule 2, to determine the direction of current or the direction of magnetic field loops. </u>