Answer:
187.38 m
Explanation:
Using the equation of motion
s = ut + 1/2gt²...................... Equation 1
Where s = distance of fall, u = initial velocity of the rock, t = time taken for the rock to fall from rest, g = acceleration due to gravity of venus.
Given: u = 0 m/s ( from rest), t = 6.5 s, g = 8.87 m/s².
substituting into equation 1
s = 0(6.5) + 1/2(8.87)(6.5)²
s = 0 + 374.7575/2
s = 187.38 m.
Hence the rock will fall 187.38 m
Explanation:
F = ma, and a = Δv / Δt.
F = m Δv / Δt
Given: m = 60 kg and Δv = -30 m/s.
a) Δt = 5.0 s
F = (60 kg) (-30 m/s) / (5.0 s)
F = -360 N
b) Δt = 0.50 s
F = (60 kg) (-30 m/s) / (0.50 s)
F = -3600 N
c) Δt = 0.05 s
F = (60 kg) (-30 m/s) / (0.05 s)
F = -36000 N
