To find the zeros of this function, we must first set the entire function equal to 0
f(x) = x² - 2x - 15 = 0
Since this is a quadratic function, we must use the quadratic formula, which is:

Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15
Now let's plug those in:

which simplifies to:

Simplified further:


And divide it by the 2 on the bottom gives us:

2+4 = 6
2-4 = -2
So the zeros of this function are
-2 and
6
Answer:
(-1, 1)
Step-by-step explanation:
Hi there!
We want to solve the system of equations given as:
2x-3y=-5
3x+y=-2
Let's solve this equation by substitution, where we will set one variable equal to an expression containing the other variable, substitute the expression as the variable that it equals, solve for the other variable (the variable that the expression contains), and then use the value of the solved variable to find the value of the first variable
In the second equation, we have y by itself; therefore, if we subtract 3x from both sides, then we will get an expression that y is equal to.
So subtract 3x from both sides
y=-3x-2
Now substitute -3x-2 as y in the first equation.
It will look something like this:
2x - 3(-3x-2)=-5
Now do the distributive property.
2x+9x+6=-5
Combine like terms
11x+6=-5
Subtract 6 from both sides
11x=-11
Divide both sides by 11
x=-1
Now substitute -1 as x in the equation y=-3x-2 to solve for y:
y=-3(-1)-2
multiply
y=3-2
Subtract
y=1
The answer is x=-1, y=1; this can also be written as an ordered pair, which would be (-1, 1)
Hope this helps!
If you would like to see another problem for additional practice, take a look here: brainly.com/question/19212538
You can make this into an inequality, using x as the number of uniforms.
100 + 12x < 61 + 15x
39 < 3x
13 < x, so they must buy more than 13 to get a better deal.
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Answer:
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