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Tpy6a [65]
3 years ago
5

Evaluate each expression -5x8+12

Mathematics
1 answer:
Oksanka [162]3 years ago
4 0
-28 because using PEMDAS you would do -5x8 which =-40 plus 12 is -28
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What is the volume of this?
bekas [8.4K]

Answer:

Step-by-step explanation:

Formula: πr^{2} h

to find the radius, multiply 6×2= 12 r=12

πr^{2}×3

to simplify that equation... π×12²×3 = 1357.168026350790679

I THINK I DID THIS CORRECTLY, SORRY IF IT IS WRONG...

8 0
3 years ago
How would you graph the solution if your inequality was I is less than or equal to 11.25?
larisa86 [58]

1 \leqslant 11.25
Depending on the scenario you would either shade everything in between these two points or it can be any real number/ point on the graph.

There isn't much info to go on how they visually want to see it.

Like you could easily graph this as a number line and shade everything from 1 to 11.25 and put a solid dot on both sides.
4 0
4 years ago
What is the equation of the line that passes through (-3, -1) and has a slope of 3/5? Put your answer in slope-intercept form. y
zubka84 [21]

Answer:

Y=3/5x -4/5

Step-by-step explanation:

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Hope this helps!

4 0
3 years ago
Each side of a square is increasing at a rate of 5 cm/s. At what rate is the area of the square increasing when the area of the
icang [17]

Answer:

<h2>70cm/s</h2>

Step-by-step explanation:

Area of a square with side of length L is expressed as A = L². The rate at which the area is increasing will be expressed as dA/dt.

dA/dt = dA/dL * dL/dt where

dL/dt is the rate at which each side of the square is increasing.

Since dA/dL = 2L, dA/dt = 2L dL/dt

Given dL/dt = 5cm/s and the Area of the square = 49 cm²

49 = L²

L = √49

L = 7cm

dA/dt = 2(7) * 5

dA/dt = 14*5

dA/dt = 70cm/s

The rate at which the area of the square is increasing is 70cm/s

3 0
3 years ago
A red die, a blue die, and a yellow die (all six sided) are rolled. we are interested in the probability that the number appeari
NISA [10]

5/54 or approximately 0.092592593  
There are 6^3 = 216 possible outcomes of rolling these 3 dice. Let's count the number of possible rolls that meet the criteria b < y < r, manually.
 r = 1 or 2 is obviously impossible. So let's look at r = 3 through 6.
 r = 3, y = 2, b = 1 is the only possibility for r=3. So n = 1
 r = 4, y = 3, b = {1,2}, so n = 1 + 2 = 3
 r = 4, y = 2, b = 1, so n = 3 + 1 = 4
 r = 5, y = 4, b = {1,2,3}, so n = 4 + 3 = 7
 r = 5, y = 3, b = {1,2}, so n = 7 + 2 = 9
 r = 5, y = 2, b = 1, so n = 9 + 1 = 10
 
 And I see a pattern, for the most restrictive r, there is 1 possibility. For the next most restrictive, there's 2+1 = 3 possibilities. Then the next one is 3+2+1
= 6 possibilities. So for r = 6, there should be 4+3+2+1 = 10 possibilities.
Let's see
 r = 6, y = 5, b = {4,3,2,1}, so n = 10 + 4 = 14
 r = 6, y = 4, b = {3,2,1}, so n = 14 + 3 = 17
 r = 6, y = 3, b = {2,1}, so n = 17 + 2 = 19
 r = 6, y = 2, b = 1, so n = 19 + 1 = 20 
 And the pattern holds. So there are 20 possible rolls that meet the desired criteria out of 216 possible rolls. So 20/216 = 5/54.
6 0
3 years ago
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