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shepuryov [24]
3 years ago
12

Most living things need oxygen to survive. These two body systems bring oxygen into your body and then move to all your body par

ts. What are these two body systems? A) respiratory and muscular B) digestive and circulatory C) respiratory and digestive D) circulatory and respiratory
Chemistry
2 answers:
77julia77 [94]3 years ago
8 0
The answer is <span>D) circulatory and respiratory</span>
Murljashka [212]3 years ago
7 0
Your answer would be D. As the circulatory system pumps oxygen rich blood through the body, and the respiratory system helps you to breath. Hope this helps!
You might be interested in
A gas occupies 800ml at a temperature of 27C. What is the volume at 132C?
pishuonlain [190]

V
1
​
/T
1
​
=V
2
​
/T
2
​

(900.0 mL) / (300.0 K) = (x) / (405.0 K); x = 1215 mL.

Change the 900 to 800, and the 300 to 27, then change the 405 to 132. And solve
3 0
3 years ago
The reaction for photosynthesis producing glucose sugar and oxygen gas is:
Anvisha [2.4K]

<u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>

To find the mass of glucose produced, first you must know the balanced reaction. For this, the Law of Conservation of Matter is followed.

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

So, in this case, the balanced reaction is:

6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the amounts of moles of each reactant and product participate in the reaction:

  • CO₂: 6 moles
  • H₂O: 6 moles
  • C₆H₁₂O₆: 1 mole
  • O₂: 6 moles

So, you know that 2.20 g of CO₂ react, whose molar weight is 44.01 g/mole. By definition of molar mass, 1 mole of CO₂ has 44.01 g. So, the number of moles that 2.20 grams of the compound represent is calculated as:

moles of CO_{2} =2.20 grams*\frac{1 mole}{44.01 grams}

moles of CO₂= 0.05 moles

Now you must follow the following rule of three: if by stoichiometry of the reaction 6 moles of CO₂ produce 1 mole of C₆H₁₂O₆, 0.05 moles of CO₂ produce how many moles of C₆H₁₂O₆?

moles of C_{6} H_{12} O_{6} =\frac{0.05moles of CO_{2} *1 mole of C_{6} H_{12} O_{6}}{6moles of CO_{2}}

moles of C₆H₁₂O₆= 8.33*10⁻³

Being the molar mass of glucose 180.18 g/mole, the mass that 8.33*10⁻³ moles of the compound represent is calculated as:

mass of glucose =8.33*10^{-3} moles*\frac{180.18 grams}{1 mole}

<em>mass of glucose= 1.5 grams</em>

Then, <u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>

5 0
3 years ago
How did Ernest Rutherford's experiment relate to J.J. Thomson's work?
olasank [31]

Answer:

D

Explanation:

I am sorry if wrong

4 0
3 years ago
Sn=0.14 (E) <br>Sn+2 = -0.15(E) <br>Which form of tin is the stronger reducing agent? OS O Sn +2? ​
fomenos

0.14

Explanation:

I just needed to finish setting up my account

3 0
2 years ago
If 495 milliliters of carbon dioxide at 25°C and 101.3 kilopascals reacts with excess water, what is the theoretical yield of ca
postnew [5]

Answer:- 1.24 g

Solution:- The balanced equation for the formation of carbonic acid by the reaction of carbon dioxide with water is:

CO_2+H_2O\rightarrow H_2CO_3

From balanced equation, there is 1:1 mol ratio between carbon dioxide and carbonic acid. So, moles of carbonic acid will be equal to the moles of carbon dioxide used.

Moles of carbon dioxide can be calculated using ideal gas law equation as it's volume, temperature and pressure are given.

we need to convert mL to L, degree C to kelvin and kilopascals to atm.

495mL(\frac{1L}{1000mL})  = 0.495 L

25 + 273 = 298 K

101.3kPa(\frac{1atm}{101.3kPa)})

= 1 atm

Ideal gas law equation is:

PV = nRT

We want to find out the n, so let's rearrange this:

n=\frac{PV}{RT}

R is the universal gas constant and it's value is \frac{0.0821atm.L}{mol.K} .

Let's pug in the values in the equation and solve it for n.

n=\frac{1*0.495}{0.0821*298}

n = 0.02 mol

To convert the moles to grams we multiply the moles by the molar mass of carbonic acid.

Molar mass of carbonic acid = 2(1.008)+12.01+3(16.00)

= 2.016+12.01+48.00

= 62.03 gram per mol (rounded to two decimal places)

Let's multiply the moles by molar mass:

0.02mol(\frac{62.03g}{mol})

= 1.24 g

So, the theoretical yield of carbonic acid is 1.24 g.


6 0
3 years ago
Read 2 more answers
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