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shepuryov [24]
3 years ago
12

Most living things need oxygen to survive. These two body systems bring oxygen into your body and then move to all your body par

ts. What are these two body systems? A) respiratory and muscular B) digestive and circulatory C) respiratory and digestive D) circulatory and respiratory
Chemistry
2 answers:
77julia77 [94]3 years ago
8 0
The answer is <span>D) circulatory and respiratory</span>
Murljashka [212]3 years ago
7 0
Your answer would be D. As the circulatory system pumps oxygen rich blood through the body, and the respiratory system helps you to breath. Hope this helps!
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Which of the following functional groups comprises a carbon atom bonded to a hydroxyl group?
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B. alcohol

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Help!!!! describe three different things that could cause climate change.(Describe two that are naturally occuring, and one that
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6 0
3 years ago
Please answer all of the examples below!
Neporo4naja [7]

Answer:

The first one is balanced. The second one is not.

Explanation:

The first one is balanced because there are the same amount of elements on the reactant side as there are on the product side. The second one is not balanced because there are not the same amount of elements on the reactant side as there are on the product side. Therefore, it is not balanced

More Detailed: first example

Reactant side (left of arrow)

H: 2

C: 1

O: 3

Product side (right of arrow)

H: 2

C: 1

O: 3

More detailed: second example

Reactant side:

Na: 1

O: 1

H: 1

C: 1

Product side:

Na: 2

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the variables needed to balance this equation is 2,1, 1, 1.

8 0
3 years ago
How do you calculate the enthalpy of formation of butaine
Gre4nikov [31]

Answer:  "Calculate the enthalpy of formation of butane, C4H10, using the balanced chemical equation and tables displaying information about enthalpy of formation/combustion. Write out the solution according to Hess's law." That's all I'm given. The key says that the answer is -125.4 kJ. C4H10   +  6.5 O2  =   4CO2  +   5 H20      The heat of combustion for one mole of butane is -2877 K.  Heats of formation from table   C02 =  -393.5 Kj/mole, H20 (g)   -241.8 Kj/mole. Heat of combustion of butane =  sum heats of formation products minus heats of formation reactants -2877 Kj =   4(-393.5Kj) + 5(-241.8Kj)    minus heat or enthalpy of formation butane.

The enthalpy formation oxygen an element is assigned a value of zero.

            -2877 Kj  =   -1582 Kj  +  -1209 Kj   minus   X

                  -2877 =  - 2791 Kj minus X

                      X =   -86 Kj.       The heats of formation for various compounds vary a little from table to table,   so   this does not quite agree with your answer.    

This is just an example

7 0
3 years ago
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