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sineoko [7]
3 years ago
8

A gold ring was purchased from a street vendor for a ridiculously low price. the buyer has brought the ring to you to conform it

s metal content. you have found the mass of the ring to be 23.46 h and its volume to be 2.25 cm3. what do you tell the buyer?
Chemistry
1 answer:
Helga [31]3 years ago
5 0

Explanation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

We are given:

Mass of liquid = 23.46 g

Volume occupied by the ring = 2.25 cm^3

Density of gold ring = D

D=\frac{23.46 g}{2.25 cm^3}=10.43 g/cm^3

Original density of gold = 19.3 g/cm^3

10.43 g/cm^3

We will tell the buyer that gold ring purchased from him is too adulterated with other metals which have reduced its density indication that it is an artificial gold ring.

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