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4 years ago

8

How many nitrogen atoms are in 4.26 moles of ammonium

1 answer:

svlad2 [7]4 years ago

7 0

Answer

0.6800 mol N.

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A helium balloon contains 16.9 L of helium at STP. How many atoms of helium are in the balloon

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4.54×10^(23) atoms He

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Oxygen is needed to produce energy in eukaryotic cells. Which organelle would you think needs oxygen the most

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Mitochondria need the most oxygen

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4 years ago

In the laboratory you dissolve 15.9 g of barium chloride in a volumetric flask and add water to a total volume of 375 ml. what i

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3 years ago

When is the Sun directly overhead in the continental United States?

astra-53 [7]

Answer:

C.

Explanation:

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6 0

3 years ago

Read 2 more answers

A tanker truck carrying 6.05×103 kg of concentrated sulfuric acid solution tips over and spills its load. The sulfuric acid solu

irinina [24]

Answer:

6,216.684 kilograms of sodium carbonate must be added to neutralize $6.05\times 10^3 kg$ of sulfuric acid solution.

Explanation:

Mass of sulfuric acid solution = $6.05\times 10^3 kg=6.05\times 10^6 g$

$1 kg = 10^3 g$

Percentage mass of sulfuric acid = 95.0%

Mass of sulfuric acid = $\frac{95.0}{100}\times 6.05\times 10^6 g$

$=5,747,500 g$

Moles of sulfuric acid = $\frac{5,747,500 g}{98 g/mol}=58,647.96 mol$

$H_2SO_4+Na_2CO_3\rightarrow Na_2SO_4+CO_2+H_2O$

According to reaction , 1 mole of sulfuric acid is neutralized by 1 mole of sodium carbonate.

Then 58,647.96 moles of sulfuric acisd will be neutralized by :

$\frac{1}{1}\times 58,647.96 mol=58,647.96 mol$ of sodium carbonate

Mass of 58,647.96 moles of sodium carbonate :

$106 g/mol\times 58,647.96 mol=6,216,683.76 g$

6,216,683.76 g = 6,216,683.76 × 0.001 kg = 6,216.684 kg

6,216.684 kilograms of sodium carbonate must be added to neutralize $6.05\times 10^3 kg$ of sulfuric acid solution.

3 0

3 years ago