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Anastasy [175]
3 years ago
14

The emission spectrum of an element:

Chemistry
1 answer:
alexandr402 [8]3 years ago
3 0

B

The emission spectrum of an element is identical to its absorption spectrum.

Explanation:

This is because a quantum leap  of an electron of an atom from one lower energy level to a higher one results in the absorption of a specific wavelength of electromagnetic radiation. When the electron leaps back to the lower energy level, it releases the same wavelength of electromagnetic radiation. This is according to Bohr's theory. Every atom has a signature absorption and emission spectra that are used to identify it.

Learn More:

For more on Bohr theory of the atom check out;

brainly.com/question/5839092

brainly.com/question/12479859

brainly.com/question/1528920

#LearnWithBrainly

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An oxygen atom has two electron shells and 6 valence electrons. how many total electrons does this atom have?
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6 electrons in total
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2. Newton began his academic career in 1667. For how long was he a working scientist? Was he a very productive scientist? Justif
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2 years ago
Energy is the work that done by a force acting through a distance And involves motion
SIZIF [17.4K]

Answer:

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Explanation:

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2 years ago
A chemical reaction occurring in a cylinder equipped with a moveable piston produces 0.641 mol of a gaseous product. If the cyli
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<u>Explanation:</u>

The relationship of number of moles and volume at constant temperature and pressure was given by Avogadro's law. This law states that volume is directly proportional to number of moles at constant temperature and pressure.

The equation used to calculate number of moles is given by:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1\text{ and }n_1 are the initial volume and number of moles

V_2\text{ and }n_2 are the final volume and number of moles

We are given:

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Putting values in above equation, we get:

\frac{2.05}{0.280}=\frac{V_2}{0.641}\\\\V_2=\frac{2.05\times 0.641}{0.280}=4.69L

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3 years ago
The Kinetic Molecular Theory (KMT) is discussed in this lesson, and it helps us understand the behavior of gases. From what we l
kiruha [24]

Answer:

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