Hich one of the following statements about orbital hybridization is incorrect?
1 answer:
Answer : The incorrect statement is, (C) The nitrogen atom in NH₃ is sp² hybridized.
Explanation :
Formula used :
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
Now we have to determine the hybridization of the following molecules.
(a) The given molecule is,
The number of electron pair are 4 that means the hybridization will be and the electronic geometry of the molecule will be tetrahedral.
(b) The given molecule is,
The number of electron pair are 2 that means the hybridization will be and the electronic geometry of the molecule will be linear.
(c) The given molecule is,
The number of electron pair are 4 that means the hybridization will be and the electronic geometry of the molecule will be tetrahedral.
But as there are 3 atoms around the central nitrogen atom, the fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be trigonal pyramidal.
(d) sp² hybrid orbitals are coplanar, and at 120° to each other.
The sp² hybrid orbitals has trigonal planar geometry and are in the same plane that means coplanar. Thus, the bond angle is 120° to each other.
(e) sp hybrid orbitals lie at 180° to each other.
The sp hybrid orbitals has linear geometry. Thus, the bond angle is 180° to each other.
Hence, the incorrect statement is, (C) The nitrogen atom in NH₃ is sp² hybridized.
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will be undissolved and sand will settle at the bottom. Here, the physical property of solubility of NaCl in water is taken into consideration. The collected water is then filtered off and evaporated to get the NaCl back from the mixture with some loss. No chemical change occurs in case of NaCl extraction from water.
Answer 2) When was to be removed from the undissolved part. The chemical property of
was used. Where it gets dissolved in acidic medium. And this way we can extract
and remove sand from it. We change the chemical composition of
by adding HCl to the mixture and dissolve
to form
which gets dissolved into the solution of HCl. Here, first decantation occurs and then extraction is done. Second, extraction is done using potassium carbonate in it which separates
from sand.
Answer 3) Here, Unknown mixture of salt and sand weighed =7.52 g (before washing);
Unknown mixture of salt and sand weighed =3.45 g (after washing);
To calculate the amount of salt in it, we can simply subtract the values of before and after washing change in weights.
The property of NaCl being soluble in water it will go away with washing leaving behind the sand only, after washing.
So, Weight of salt was = 7.52g - 3.45 g = 4.07g
To find the percentage of sand that was mixed with salt =
(3.45 g sand / 7.52g of mixture) X 100 = 45.9% sand was mixed with salt.
To verify whether the correct percentage of salt and sand was calculated we can recheck the value for salt as well.
(4.07 g of salt / 7.52g of mixture) X 100 = 54.1% salt
On adding we get, 45.9% + 54.1% = 100%.
Which confirms that the calculations are correct.
Answer:
The electronic configuration of Na is b