All categories

3 years ago

TIMED PLS HELP AND WILL GIVE BRAINLIST

Chemistry

1 answer:

Strike441 [17]3 years ago

6 0

Answer:

19.4 g of alum, will be its theoretical yield

Explanation:

The reaction is:

2 Al + 2 KOH + 4 H₂SO₄ + 22H₂O → 3H₂ + 2KAl(SO₄)₂•12H₂O

Let's determine the amount of acid.

M are the moles contained in 1 L of solution or it can be mmoles that are contained in 1 mL of solution

M = mmol /mL

M . mL = mmol

We replace: 8.3 mL . 9.9 M = 82.17 mmoles

We convert to moles: 82.17 mmol . 1 mol / 1000mmol = 0.082 moles

Ratio is 4:2

4 moles of sulfuric acid can make 2 moles of alum

By the way, 0.082 moles of acid may produce ( 0.082 . 2) /4 = 0.041085 moles.

We convert moles to mass:

Molar mass of alum is: 473.52 g/mol.

0.041085 moles . 473.52 g/mol = 19.4 g

You might be interested in

What is the OH- of {H+} = 4.0 x 10 to the power of -8

True [87]

Answer:

At standard room temperature, $[{\rm OH^{-}] \approx 2.5 \times 10^{-7}\; \rm M$ when $[{\rm H^{+}] = 4.0 \times 10^{-8}\; \rm M$ .

Explanation:

The following equilibrium goes on in water:

${\rm H_{2}O}\, (l) \rightleftharpoons {\rm H^{+}}\, (aq) + {\rm OH^{-}}\, (aq)$ .

The forward reaction is known as the self-ionization of water. The ionization constant of water, $K_{\rm w}$ , gives the equilibrium position of this reaction:

$K_{\rm w} = [{\rm H^{+}] \cdot [{\rm OH^{-}}]$ .

At standard room temperature ( $25\; {\rm ^{\circ}C}$ ), $K_{\rm w} \approx 10^{-14}$ . Also, $[{\rm H^{+}}] = 4.0 \times 10^{-8}\; \rm mol \cdot L^{-1}$ . Substitute both values into the equation and solve for $[{\rm OH^{-}}]$ .

$\begin{aligned} {[}{\rm OH^{-}}{]} &= \frac{K_{\rm w}}{[{\rm H^{+}}]} \\ &\approx \frac{10^{-14}}{4.0 \times 10^{-8}} = 2.5 \times 10^{-7}\end{aligned}$ .

In other words, in an aqueous solution at standard room temperature, $[{\rm OH^{-}] \approx 2.5 \times 10^{-7}\; \rm M$ when $[{\rm H^{+}] = 4.0 \times 10^{-8}\; \rm M$ .

5 0

3 years ago

Match each weather phenomena listed below to its appropriate scale of motion. longwave ridges and troughs microscale a high pres

Ipatiy [6.2K]

Answer:

Longwave ridges = Global scale

High pressure system persists over the central plains for 4 days = Synoptic scale

Supercell thunderstorm that lasts for over an hour = mesoscale

A turbulent eddy = microscale

Explanation:

Global scale has a range of the entire earth

synoptic scale has a range of about 100-1000km and can last fro days to weeks

mesoscale has a range of 4-100km and lasts for a day maximum

microscale is the least of all atmospheric motions.

6 0

3 years ago

What type of extinguisher will extinguish a class a, b or c fire?

RUDIKE [14]

Any fire extinguisher should put out a fire, that is unless the extinguisher is old and faulty.

7 0

4 years ago

How do you convert kilometers to grams

IRISSAK [1]

By multiplying the mass value by 1000.

3 0

3 years ago

Read 2 more answers

How many neutrons does the most common isotope of hydrogen have?

Lorico [155]

Protium - the most common isotope of hydrogen - has no neutrons in its nucleus.

3 0

3 years ago