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mote1985 [20]
3 years ago
10

A 3.9 kg ball traveling towards a soccer player at a velocity of -3.5 m/s rebounds off the soccer player's foot at a velocity of

+15.9 m/s. If the Force of contact between the ball and the player's foot was 25.9 N. For how long was the force applied?
Physics
1 answer:
Tresset [83]3 years ago
4 0

Answer: 2.92 s

Explanation:

Given

Mass of ball is m=3.9\ kg

The initial velocity of the ball is u=-3.5\ m/s

Velocity after the rebound is v=15.9\ m/s

Force during the contact is F=25.9\ N

We know, change in momentum is Impulse

\Rightarrow F\cdot \Delta t=m(\Delta v)

\Rightarrow 25.9\cdot \Delta t=3.9(15.9-(-3.5))\\\\\Rightarrow \Delta t=\dfrac{3.9\times 19.4}{25.9}=2.92\ s

Thus, the force is applied for 2.92 s

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