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IgorLugansk [536]
3 years ago
11

In a titration, 25.0 mL of KHP is titrated to the equivalence point with NaOH. The final solution volume is 45.5 mL. What was th

e volume of NaOH used in the titration?
25.0 mL

20.5 mL

70.5 mL

45.5 mL
Chemistry
2 answers:
alukav5142 [94]3 years ago
6 0
I think it A because it 25.0 ml
Illusion [34]3 years ago
3 0

Answer:

20.5 mL was the volume of NaOH used in the titration.

Explanation:

Volume of KHP taken = 25.0 mL

Volume of NaoH taken for titration = x

Total volume of the solution = 45.5 mL

45.5 mL = 25.0 mL + x

x = 45.5 ml - 25.0 mL = 20.5 mL

20.5 mL was the volume of NaOH used in the titration.

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A golf pro has 2100 J of kinetic energy and swings his driver which weighs .75 kg. What is the speed of his swing?
jeka57 [31]

Answer : The correct answer is 74.83 m/s .

The kinetic energy is energy possessed by any mass which is moving or have some speed . It is product of mass and velocity . It is expressed as :

KE = \frac{1}{2}  * m* v^2

Where KE = kinetic energy in J or kg\frac{m^2}{s^2} m = mass in Kg v = speed in m/s²

Unit of KE is Joules (J) .

Givne : KE = 2100 J mass = 0.75 kg v = ?

Plugging value in KE formula =>

2100 J = \frac{1}{2}  * 0.75 Kg * v^2

2100 J = 0.375 Kg * v^2

Dividing both side by 0.375 kg =>

\frac{2100 J}{0.375 Kg}  = \frac{0.375 Kg}{0.375 Kg } * v^2

v^2 = 5600 \frac{m^2}{s^2}

v= 74.83 \frac{m}{s}

8 0
4 years ago
Read 2 more answers
The initial volume of a gas at a pressure of 3 atm is 5.2 L. What will the volume be if the pressure is increased to 15 atm?
julsineya [31]

Answer:

1 L

Explanation:

Use Boyle's Law, which is defined as:

p1v1 = p2v2

p1 = 3atm

v1 = 5.2L

p2 = 15atm

v2 = ?

We are solving for v2 because all other variables are given.

p1v1 = p2v2

(3atm)(5.2L) = (15atm)(v2)

v2 = (3)(5.2) / (15) = 1.04 L ≈ 1 L

5 0
3 years ago
When a diprotic acid, , is titrated with , the protons on the diprotic acid are generally removed one at a time, resulting in a
marshall27 [118]

Answer:

At the second equivalent point 200 mL of NaOH is required.

Explanation:

at the first equivalent point:

                              H2A    +     OH-       =     HA-  +     H2O

initial mmoles        y*100         y*100            -                -

final mmoles            0                0                 y*100       y*100

at the second equivalent point:

                              HA-    +     OH-       =     A2-  +     H2O

initial mmoles        y*100         y*100            -                -

final mmoles            -                -                 y*100       y*100

at the second equivalent point we have that y*100 mmoles of NaOH or 100 mL of NaOH ir required, thus:

at the second equivalent point 200 mL of NaOH is required.

4 0
4 years ago
3. A sample of air in a syringe exerts a pressure of 1.02 atm at 22.0°C. The syringe is placed in a boiling-water bath at 100.0°
inysia [295]

Answer:

0.214 mL    

explanation:

8 0
3 years ago
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