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3 years ago

9

What are the representative particles of elements, ionic compounds, and covalent compounds called?

1 answer:

vesna_86 [32]3 years ago

3 0

Protons are the representative particles of elements, ionic compounds, and covalent compounds.

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What force is required to accelerate a body with a mass of 15 kilograms at a rate of 8 m/s²?

mihalych1998 [28]

Newton's Second law of motion:

Force = (mass) x (acceleration)

Force = (15kg) x (8m/s²) = 120 kg-m/s² = 120 newtons

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3 years ago

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At a rock concert, the sound intensity 1.0 m in front of the bank of loudspeakers is 0.10 W/m². A fan is 30 m from the loudspeak

Klio2033 [76]

To solve this problem we will apply the concepts related to the Area, the power and the proportionality relationships between intensity and distance.

The expression for sound power is,

$P = AI$

Here,

A = Area

I = Intensity

P = Power

At the same time the area can be written as,

$A = \frac{\pi d^2}{4}$

Now the intensity is inversely proportional to the square of the distance from the source, then

$I \propto \frac{1}{r^2}$

The expression for the intensity at different distance is

$\frac{I_1}{I_2}= \frac{r^2_2}{r_1^2}$

Here,

$I_1$ = Intensity at distance 1

$I_2$ = Intensity at distance 2

$r_1$ = Distance 1 from light source

$r_2$ = Distance 2 from the light source

If we rearrange the expression to find the intensity at second position we have,

$I_2 = I_1 (\frac{r_1^2}{r_2^2})$

If we replace with our values at this equation we have,

$I_2 = (0.10W/m^2)(\frac{1.0m^2}{30.0m^2})$

$I_2 = 1.11*10^{-4} W/m^2$

Now using the equation to find the area we have that

$A = \frac{\pi (8.4*10^{-3}m)^2}{4}$

$A = 5.5*10^{-5}m^2$

Finally with the intensity and the area we can find the sound power, which is

$P = AI$

$P = (5.5*10^{-5}m^2)(1.11*10^{-4}W/m^2)$

$P = 6.1*10^{-9}J/s$

Power is defined as the quantity of Energy per second, then

$E = 6.1*10^{-9}J$

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3 years ago

How are thunderstorms kept alive?

Burka [1]

Answer:

E step leader

Explanation:

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2 years ago

A double slit that is illuminated with coherent light of wavelength 644 nm produces a pattern of bright and dark fringes on a sc

shutvik [7]

Answer:

$2.77$ cm

Explanation:

$d$ = separation between the slits = 2783 x 10⁻⁹ m

$\lambda$ = wavelength of coherent light = 644 nm = 644 x 10⁻⁹ m

$D$ = Distance of the screen = 6 cm = 0.06 m

$y_{n}$ = Position of nth bright fringe

Position of nth bright fringe is given as

$y_{n} = \frac{nD\lambda }{d}$

for n = 2

$y_{2} = \frac{nD\lambda }{d}$

$y_{2} = \frac{(2)(0.06)(644\times10^{-9}))}{2783\times10^{-9}}$

$y_{2} = 0.0278$ m

for n = 4

$y_{4} = \frac{nD\lambda }{d}$

$y_{4} = \frac{(4)(0.06)(644\times10^{-9}))}{2783\times10^{-9}}$

$y_{4} = 0.0555$ m

Distance between 4th and 2nd bright fringes is given as

$w = y_{4} - y_{2} = 0.0555 - 0.0278 = 0.0277 m$

$w = 2.77$ cm

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3 years ago

Adita lifts a book from the floor, carries it across the room, and places it on a high shelf. When is Adita doing work on the bo

noname [10]

She does work from the moment she touches the book until she lets it go. Work is anything that requires energy. Therefore, she is working as she picks up the book, carries it, and when she is lifting it onto the shelf.

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3 years ago

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