The answer is D, use Pythagorean theorem.
For every 2 moles of CO and 1 mole of O2, 2 moles of CO2 will be produced.
The ratio is 2:1:2.
Hope this helps! :)
Answer:
Part A. 1.355 mol/L
Part B. 0.100 mol
Part C. 74.0 mL
Explanation:
Part A.
The molar mass of luminol is 177.16 g/mol, so the number of moles at 18.0 g is:
n = mass/molar mass
n = 18.0/177.16
n = 0.1016 mol
The molarity is the number of moles divided by the volume (0.075 L)
C = 0.1016/0.075
C = 1.355 mol/L
Part B.
The number of moles is the molarity multiplied by the volume, so:
n = 5.00x10⁻² mol/L * 2.00 L
n = 0.100 mol
Part C.
To prepare a solution by dilution, we can use the equation
C1V1 = C2V2
Where C1 is the concentration of the initial (stock) solution, V1 is its volume necessary, C2 is the concentration of the diluted solution, and V2 is its volume.
Thus, C1 = 1.355 M, C2 = 0.05 M, V2 = 2.00 L
1.355V1 = 0.05*2
V1 = 0.074 L
V1 = 74.0 mL
Tungsten (W) is in the 6th period and 6th family of the periodic table.
