Question

Calculate the value of two equal charges if they repel one another with a force of 10 N having 10 m distance apart in a vacuum. What would be the size of the charges if they were situated in an insulting liquid whose permittivity was ten times that of a vacuum.
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Answer 1

Explanation:

a) From Coulombs law,

F = (kq1q2)/r²...............1

F = 10 N

r = 10m

k = 9 × 10^9 m/F

q1 = q2

from equation 1, make q the subject

q = (Fr²)/2k

q = (10×10²)/(2×9×10^9)

q = 1000/1.8×10^10

q = 5.556×10^-8 C

b) K = k/ko

k = Kko = 10times permittivity of free-space

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