Answer: Your code returns a number of 99.123456789 +0.00455679
Ok, you must see where the error starts to affect your number.
In this case, is in the third decimal.
So you will write 99.123 +- 0.004 da da da.
But you must round your results. In the number you can see that after the 3 comes a 4, so the 3 stays as it is.
in the error, after the 4 comes a 5, so it rounds up.
So the final presentation will be 99.123 +- 0.005
you are discarding all the other decimals because the error "domains" them.
Here we can say that rate of flow must be constant
so here we will have
![A_1v_1 = 18 A_2v_2](https://tex.z-dn.net/?f=A_1v_1%20%3D%2018%20A_2v_2)
now we know that
![A_1 = 1 cm^2](https://tex.z-dn.net/?f=A_1%20%3D%201%20cm%5E2)
![A_2 = 0.4 cm^2](https://tex.z-dn.net/?f=A_2%20%3D%200.4%20cm%5E2)
now from above equation
![1 cm^2 v_1 = 18(0.400 cm^2)v_2](https://tex.z-dn.net/?f=1%20cm%5E2%20v_1%20%3D%2018%280.400%20cm%5E2%29v_2)
![\frac{v_2}{v_1} = \frac{1}{18\times 0.4}](https://tex.z-dn.net/?f=%5Cfrac%7Bv_2%7D%7Bv_1%7D%20%3D%20%5Cfrac%7B1%7D%7B18%5Ctimes%200.4%7D)
![\frac{v_2}{v_1} = 0.14](https://tex.z-dn.net/?f=%5Cfrac%7Bv_2%7D%7Bv_1%7D%20%3D%200.14)
so velocity will reduce by factor 0.14
Answer:
momentum=mass×velocity
momentum =400kg×20m/s=8000kg.m/s