Under the assumption that the tires do not change in volume, apply Gay-Lussac's law:
P/T = const.
P = pressure, T = temperature, the quotient of P/T must stay constant.
Initial P and T values:
P = 210kPa + 101.325kPa
P = 311.325kPa (add 101.325 to change gauge pressure to absolute pressure)
T = 25°C = 298.15K
Final P and T values:
P = ?, T = 0°C = 273.15K
Set the initial and final P/T values equal to each other and solve for the final P:
311.325/298.15 = P/273.15
P = 285.220kPa
Subtract 101.325kPa to find the final gauge pressure:
285.220kPa - 101.325kPa = 183.895271kPa
The final gauge pressure is 184kPa or 26.7psi.
Answer:
The focal length of the concave mirror is -15.5 cm
Explanation:
Given that,
Height of the object, h = 20 cm
Radius of curvature of the mirror, R = -31 cm (direction is opposite)
Object distance, u = -94 cm
We need to find the focal length of the mirror. The relation between the focal length and the radius of curvature of the mirror is as follows :
R = 2f
f is the focal length


f = -15.5 cm
So, the focal length of the concave mirror is -15.5 cm. Hence, this is the required solution.
The change in gravitational potential energy is A) 15.68 J
Explanation:
The gravitational potential energy of an object is the energy possessed by the object due to its position in the gravitational field.
The change in gravitational potential energy of an object is given by the equation:

where
m is the mass of the object
is the acceleration due to gravity
is the change in height of the object
In this problem, we have
m = 2 kg is the mass of the frame
is the change in height
Substituting, we find:

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Answer:
The length of the closed tube is<u> </u>
<u>0.81 m</u>
Explanation:
Formula used :

Speed = v = 346 m/s


wavelength = 0.81 m