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aleksley [76]
3 years ago
9

for a body moving in a straight line / its distance and displacement can be same. justify with an example?

Physics
1 answer:
Tema [17]3 years ago
6 0
The distance of an object is the total distance it travels, while the displacement of the object is how far away the object is from the starting point.

Because the body is moving in a STRAIGHT line, that means it does not change directions, therefore when the body gets to the destination, the total distance will be the same as the displacement. If the body were to change directions, then the magnitude of the vectors will need to be added up and calculated.

For example, let's say you are walking to your friends house directly across the street from your house. All you need to do is walk in a strsight line from the front of your house and you will get to your friends house. The distance and displacement will be the same.

Now if your friend lived right across the street, but 5 houses down, and you cross the street directly from your house then turn in another direction and walk straight, then the distance in this case will quite likely be greater than the displacement because the displacement is the distance from your house to your friends house when measured diagonally.
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Answer:

196.34 °F

Explanation:

To convert from degrees celsius to degrees fahrenheit, use this equation:

(°C * 9/5) + 32 = °F

So, using this equation:

(91.30 * 9/5) + 32 = °F

196.34 + 32 = °F

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Hope this helps!

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4 years ago
Two children, Ahmed and Jacques, ride on a merry-go-round. Ahmed is at a greater distance from the axis of rotation than Jacques
Alex

Answer:

A. Ahmed has a greater tangential speed than Jacques.

D. Jacques and Ahmed have the same angular speed.

Explanation:

Kinematics of the merry-go-round

The tangential speed of the merry-go-round is calculated using the following formula:

v = ω*R

Where:

v is the tangential speed in meters/second (m/s)

ω is the angular speed in radians/second (rad/s)

R is the angular speed in meters (m)

Data

dA = RA  : Ahmed distance to the axis of rotation

dJ = RJ   : Jacques distance to the axis of rotation

Problem development

We apply the formula (1)

v = ω*R

vA= ω*RA : Ahmed  tangential speed

vJ= ω*RJ  :  Jacques  tangential speed

Ahmed is at a greater distance from the axis of rotation than Jacques, then,

RA ˃ RJ and Ahmed and Jacques have the same  speed ω, then:

vA ˃ vJ

6 0
3 years ago
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Answer:

D) A warm front brings drizzly weather.

Explanation:

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3 years ago
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44 = 0 + 5 * t so t = 44 / 5 = 8.8 hours

4 0
3 years ago
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