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aleksley [76]
3 years ago
9

for a body moving in a straight line / its distance and displacement can be same. justify with an example?

Physics
1 answer:
Tema [17]3 years ago
6 0
The distance of an object is the total distance it travels, while the displacement of the object is how far away the object is from the starting point.

Because the body is moving in a STRAIGHT line, that means it does not change directions, therefore when the body gets to the destination, the total distance will be the same as the displacement. If the body were to change directions, then the magnitude of the vectors will need to be added up and calculated.

For example, let's say you are walking to your friends house directly across the street from your house. All you need to do is walk in a strsight line from the front of your house and you will get to your friends house. The distance and displacement will be the same.

Now if your friend lived right across the street, but 5 houses down, and you cross the street directly from your house then turn in another direction and walk straight, then the distance in this case will quite likely be greater than the displacement because the displacement is the distance from your house to your friends house when measured diagonally.
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You and a friend each carry a 15 kg suitcase up two flights of stairs, walking at a constant speed. Take each suitcase to be the
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Answer:

Both of you did the same work but you expended more power.

Explanation:              

<em>Work done</em> by an object is calculated by force applied multiplied by the distance.

  W=F*d

From the figure given below let us calculate force applied bith you and yopur friend.

Let us take the stairs in positive x direction,

Work done by you W₁ ,

The force applied Fₓ = F - mgsinθ =maₓ

here aₓ = 0, because both of you move with constant speed

F - mgsinθ = 0

F=  mgsinθ

The work done by you on the suitcase is

W = F L cos0°  ,    where L is he length of the staircase.

W = FL = mgsinθL ,  by substituting value of F

Work done by you is W₁ = mgLsinθ

Similarly work done by your friend is W₂ = mgLsinθ.

Because both of you carry suitcase of same weight and in staircase is in same angle the force applied is same .

Therefore <em>work done by both of you is same</em> . Both of you did equal work.

The power , is defined as amount of energy converted or transfered per second or rate at which work is done .

P =\frac{W}{t} =\frac{FL}{t}

Power spend by you P₁ = mgLsinθ/t

P₁ = 15*9.8*Lsinθ/30

P₁ = 4.9L sinθ  eqn 1

Power spend by your friend is P₂ = mgLsinθ/t

P₂ =15*9.8*Lsinθ/60

P₂ = 2.45Lsinθ    eqn 2

Dividing eqn 1 and eqn 2

P₁ = 2P₂

You have spend more power than your friend .

Hence Both of you did equal work but you spend more power.

7 0
3 years ago
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