Explanation:
If two particles are involved in an elastic collision, the velocity of the second particle after collision can be expressed as: v2f=2⋅m1(m2+m1)v1i+(m2−m1)(m2+m1)v2i v 2 f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i .
Answer: rp/re= me/mp= 544 * 10^-6.
Explanation: To calculate this problem we have to consider the circular movement by the electron and proton inside a magnetic field.
Then the dynamic equation for the circular movement is given by:
Fcentripetal= m*ω^2.r
q*v*B=m*ω^2.r
we write this for each particle then we have the following:
q*v*B=me* ω^2*re
q*v*B=mp* ω^2*rp
rp/re=me/mp=9.1*10^-31/1.67*10^-27=544*10^-6
Explanation:
potential energy= mgh
30 × 10 × 30 = 9000J or 9KJ
Answer:
Explanation:
Given
Density of Cork 
Considering V be the volume of Cork
Buoyant Force will be acting Upward and Weight is acting Downward along with T
Since density of water is more than cork therefore Cork will try to escape out of water but due to tension it will not
we can write as
where T=tension
Thus Tension T is
Taking 
common
Answer:
t = 13.43 s
Explanation:
In order to find the minimum time required by the plane to stop, we will use the first equation of motion. The first equation of motion is written as follows:
Vf = Vi + at
where,
Vf = Final Velocity of the Plane = 0 m/s (Since, the plane finally stops)
Vi = Initial Velocity of the Plane = 95 m/s
a = deceleration of the plane = - 7.07 m/s²
t = minimum time interval needed to stop the plane = ?
Therefore,
0 m/s = 95 m/s + (- 7.07 m/s²)t
t = (95 m/s)/(7.07 m/s²)
<u>t = 13.43 s</u>
