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True [87]
3 years ago
8

The impulse given to a ball with mass of 2 kg is 16 N*s. If the ball starts from rest, what is its final velocity?

Physics
2 answers:
Alik [6]3 years ago
7 0
The impulse is equal to the variation of momentum of the object:
I=\Delta p = m \Delta v
where m is the mass object and \Delta v = v_f - v_i is the variation of velocity of the object.

The ball starts from rest so its initial velocity is zero: v_i=0. So we can rewrite the formula as
I=m v_f
or 
v_f =  \frac{I}{m}

and since we know the impulse given to the ball (I=16 Ns) and its mass (m=2 kg), we can find the final velocity of the ball:
v_f =  \frac{16 Ns}{2 kg}=  8 m/s
adelina 88 [10]3 years ago
6 0

Answer:

8 m/s

Explanation:

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Generally, the equation for work  is mathematically given as

Wt=wac+Wc+Wba

Therefore

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8 0
2 years ago
A ball rolls 60 centimeters along a sidewalk in 5 seconds what is the speed of the ball.
meriva

Answer:

12 cm/s

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Well, for one thing, it could depend on which fruit is dropped first. You haven't mentioned that.

If they're both dropped at exactly the same time, then the melon at 32m hits the ground first.

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