Answer:
0.63m
Explanation:
Volume expansivity = change in volume/original volume×temp change
Volume expansivity p = 3x
p = ∆V/V∆t
x is the linear expansivity
Given
x = 6 x 10^-4
p = 3x
p = 3(6 x 10^-5)
p = 18×10^-5
Volume = 100m³
∆t = 45-10 = 35°C
Required
Change in volume ∆V
Substitute the given values into the formula
18×10^-5 = ∆V/100(35)
18×10^-5 =∆V/3500
∆V = 3500×0.00018
∆V = 0.63m
Hence the increase in volume of the Mercury is 0.63n
Answer:
Force,F =
Explanation:
Given that,
Charge 1,
Charge 2,
Negative charge is 0.002 m north of a positive charge, distance between charges, d = 0.002 m.
Let is the magnitude of electrical force applied by q₁ on q₂. We know that the electrical force is given by the formula as follows :
So, the electrical force applied by q₁ on q₂ is towards north.
Answer:
Explanation:
We know that Impulse = force x time
impulse = change in momentum
change in momentum = force x time
Force F = .285 t -.46t²
Since force is variable
change in momentum = ∫ F dt where F is force
= ∫ .285ti - .46t²j dt
= .285 t² / 2i - .46 t³ / 3 j
When t = 1.9
change in momentum = .285 x 1.9² /2 i - .46 x 1.9³ / 3 j
= .514i - 1.05 j
final momentum
= - 3.1 i + 3.9j +.514i - 1.05j
= - 2.586 i + 2.85j
x component = - 2.586
y component = 2.85