For three moles of an ideal gas are taken around the eye, the total work for the cycle is mathematically given as
Wt=1945.475J
<h3>What is the total work F for the cycle.(R=8.31J/molK)?</h3>
Generally, the equation for work is mathematically given as
Wt=wac+Wc+Wba
Therefore
Wac=Pa(Vc-Va)=nR(Tc-Ta)
Wac=3(8.314*192)
Wac=4788.864J
Wcb=P1v1-p2v2/v-1
Wcb-3*8.34*108/0.4
Wcb=-6734.34J
Wab=0
In conclusion,
Wt=wac+Wc+Wba
Wt=4788.864J+0+(-6734.34J)
Wt=+1945.475J
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Answer:
12 cm/s
Explanation:
Quite simply, you are looking for cm/s
so 60 cm / 5s = 12 cm/s
<span> Allied Forces. they became the allies.</span>
Well, for one thing, it could depend on which fruit is dropped first. You haven't mentioned that.
If they're both dropped at exactly the same time, then the melon at 32m hits the ground first.
It has nothing to do with their masses or weights. It's only a matter of which one has farther to fall. Even if it were a school-bus at 96m instead of a pomegranate, anything dropped from less than 96m would reach the ground in less time than the school-bus.