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LekaFEV [45]
3 years ago
9

While Bob is demonstrating the gravitational force on falling objects to his class, he drops an 1.0 lb bag of feathers from the

top of the science building. Determine the distance the bag has traveled after falling for 1.5 seconds assuming it has reach free fall and given the gravitational acceleration of 9.8 m/sec2.
Physics
1 answer:
BartSMP [9]3 years ago
3 0

In the experiment of free fall bob released a bag of mass 1 lb

so here we can say that initial speed of the bag is Zero

time taken by the bag to free fall is given as

t = 1.5 s

also the acceleration of free fall is given as

a = 9.8 m/s^2

now we will use kinematics equation here for finding the distance of free fall

d = v_i * t + \frac{1}{2} at^2

d = 0 + \frac{1}{2}*9.8* 1.5^2

d = 4.9 * 2.25

d = 11.025 m

so the bag will fall down by total distance of 11.025 m from its initial released position.


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jolli1 [7]

Answer:

false

Explanation:

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A hot-air balloon is accelerating upward under the influence of two forces, its weight and the buoyant force. for simplicity, co
Elenna [48]
Let V = the volume of the balloon
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Mass of the balloon m = V ?hot

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A playground merry-go-round has a radius of 4.6 m and a moment of inertia of 200 kg-m2 and turns with negligible friction about
tankabanditka [31]

Answer:

8050 J

Explanation:

Given:

r = 4.6 m

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Fr = Iα

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α = 0.598 rad/s²

Now you can find the final angular velocity, then use that to find the rotational energy:

ω = αt

ω = (0.598 rad/s²) (15.0 s)

ω = 8.97 rad/s

W = ½ I ω²

W = ½ (200 kg m²) (8.97 rad/s)²

W = 8050 J

Or you can find the angular displacement and find the work done that way:

θ = θ₀ + ω₀ t + ½ αt²

θ = ½ (0.598 rad/s²) (15.0 s)²

θ = 67.3 rad

W = τθ

W = Frθ

W = (26.0 N) (4.6 m) (67.3 rad)

W = 8050 J

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