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LekaFEV [45]
3 years ago
9

While Bob is demonstrating the gravitational force on falling objects to his class, he drops an 1.0 lb bag of feathers from the

top of the science building. Determine the distance the bag has traveled after falling for 1.5 seconds assuming it has reach free fall and given the gravitational acceleration of 9.8 m/sec2.
Physics
1 answer:
BartSMP [9]3 years ago
3 0

In the experiment of free fall bob released a bag of mass 1 lb

so here we can say that initial speed of the bag is Zero

time taken by the bag to free fall is given as

t = 1.5 s

also the acceleration of free fall is given as

a = 9.8 m/s^2

now we will use kinematics equation here for finding the distance of free fall

d = v_i * t + \frac{1}{2} at^2

d = 0 + \frac{1}{2}*9.8* 1.5^2

d = 4.9 * 2.25

d = 11.025 m

so the bag will fall down by total distance of 11.025 m from its initial released position.


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For a constant acceleration, distance = 402.3


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vector u has a magnitude of 20 and direction of 0°.vector v has amagnitude of 40and a direction of 60°.find the magnitude and di
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Addition of vectors:

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a) Find the magnitude and direction of the resultant to the nearest whole

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Vector Sum:

The resultant of two vectors is simply the vector sum of the vectors. There are a handful of ways to present the resultant factor; the notation that shows the vector magnitude and direction is called the polar vector notation. An example of a vector presented in polar vector notation is

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For the vector →u of magnitude 20 and direction 0∘ to the horizontal axis, the vector is →u=^i20.

For the vector →v

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The resultant vector →w is the vector sum of the vectors, i.e.

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=^i(20+40cos60∘)+^j(40sin60∘)

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For a vector ^ix+^jy, the magnitude of the vector is √x2+y2 and the direction above the horizontal axis is θ=tan−1(yx).

Let's use the formulas:

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The magnitude of the vector is about 53 units in the direction 41-degrees above the horizontal axis.

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Answer:

Explanation:

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