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LekaFEV [45]
3 years ago
9

While Bob is demonstrating the gravitational force on falling objects to his class, he drops an 1.0 lb bag of feathers from the

top of the science building. Determine the distance the bag has traveled after falling for 1.5 seconds assuming it has reach free fall and given the gravitational acceleration of 9.8 m/sec2.
Physics
1 answer:
BartSMP [9]3 years ago
3 0

In the experiment of free fall bob released a bag of mass 1 lb

so here we can say that initial speed of the bag is Zero

time taken by the bag to free fall is given as

t = 1.5 s

also the acceleration of free fall is given as

a = 9.8 m/s^2

now we will use kinematics equation here for finding the distance of free fall

d = v_i * t + \frac{1}{2} at^2

d = 0 + \frac{1}{2}*9.8* 1.5^2

d = 4.9 * 2.25

d = 11.025 m

so the bag will fall down by total distance of 11.025 m from its initial released position.


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The coefficients of static and kinetic frictions for plastic on wood are 0.50 and 0.40,respectively. How much horizontal force w
IrinaK [193]

The horizontal force needed to start the calculator moving from rest is 1.5 N

What is Kinetic friction?

It is defined as a force that acts between moving surfaces.

The magnitude of the force will depend on the coefficient of kinetic friction between the two materials.

Here,

weight of calculator, N = 3 N

The coefficients of static frictions, µ (static) = 0.50

The coefficients of kinetic frictions, µ (kinetic) = 0.40

Now,

The horizontal force required = The static friction force

F = µ (static) * weight of calculator

F = 0.50 * 3.0

F = 1.5 N

Hence,

The horizontal force needed to start the calculator moving from rest is 1.5 N

Learn more about   horizontal force here:

<u>brainly.com/question/21481680</u>

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5 0
2 years ago
The component of the external magnetic field along the central axis of a 78-turn circular coil of radius 34.0 cm decreases from
grigory [225]

Answer:

Induced current, I = 18.88 A

Explanation:

It is given that,

Number of turns, N = 78

Radius of the circular coil, r = 34 cm = 0.34 m

Magnetic field changes from 2.4 T to 0.4 T in 2 s.

Resistance of the coil, R = 1.5 ohms

We need to find the magnitude of the induced current in the coil. The induced emf is given by :

\epsilon=-N\dfrac{d\phi}{dt}

Where

\dfrac{d\phi}{dt} is the rate of change of magnetic flux,

And \phi=BA

\epsilon=-NA\dfrac{dB}{dt}

\epsilon=-78\times \pi (0.34)^2\dfrac{(0.4-2.4)}{2}

\epsilon=28.32\ V

Using Ohm's law, \epsilon=I\times R

Induced current, I=\dfrac{\epsilon}{R}

I=\dfrac{28.32}{1.5}

I = 18.88 A

So, the magnitude of the induced current in the coil is 18.88 A. Hence, this is the required solution.

5 0
3 years ago
In Milgram's experiment:
SpyIntel [72]

Answer:

B. The "Learner" was working with Milgram.

Explanation:

just took the test

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3 0
2 years ago
Peer assessment is a unique educational model. Think back to how you felt about peer assessment at the beginning of the term, an
luda_lava [24]

Answer:

In the beginning, I was not familiar to assess assessments of the other students. Ifelt a little bit weird that is it possible to check assignments while having an instructor.I was also a bit frustrated, to be honest, that why do we have to assess thoseassessments. It was kind of extra burden for me. But after few weeks assessingmore assignments, my feeling had changed because I was learning lots of thingsthat were changing my perspectives. I was gaining extra knowledge from my peersin the form of assessments. Yes, I am comfortable with assessing assessments,because I got to learn many vocabularies and making structures of the sentencecorrectly by improving grammatically as I am not a native English speaker. Thus, inthis way, I was learning something new in each and every assessment.

8 0
3 years ago
Read 2 more answers
Julian tests four springs and records the results in the table
Tju [1.3M]

Answer:

list of spring in order of increasing spring constant is given by,

W, Y, X, Z

Explanation:

Spring W:

Magnitude of Force applied on the spring is given by,

F = k x

Where, F = force applied

k = spring constant

x displacement

k = F/x

k = 20 / 0.5

k = 40 N/m

Spring X:

Magnitude of Force applied on the spring is given by,

F = k x

Where, F = force applied

k = spring constant

x displacement

k = F/x

k = 60 / 0.3

k = 200 N/m

Spring Y:

Magnitude of Force applied on the spring is given by,

F = k x

Where, F = force applied

k = spring constant

x displacement

k = F/x

k = 40 / 0.4

k = 100 N/m

Spring Z:

Magnitude of Force applied on the spring is given by,

F = k x

Where, F = force applied

k = spring constant

x displacement

k = F/x

k = 50 / 0.1

k = 500 N/m

Thus, list of spring in order of increasing spring constant is given by,

W, Y, X, Z





8 0
3 years ago
Read 2 more answers
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