K.E=0.5*mv²
v=square root 2ke/m
v= square root 2*8J/1 kg
v= 4 m/s
To solve this process it is necessary to consider the concepts related to the relations between pressure and temperature in an adiabatic process.
By definition the relationship between pressure and temperature is given by
Here
P = Pressure
T = Temperature
The ratio of specific heats. For air normally is 1.4.
Our values are given as,
Therefore replacing we have,
Solving for
Therefore the maximum theoretical pressure at the exit is
Answer:
9.75 x 10^4 J
Explanation:
Work done, W = 9.75 x 10^4 J
According to the work energy theorem, the change in kinetic energy is equal to the work done by all the forces.
So, here work done is 9.75 x 10^4 J so the change in kinetic energy is 9.75 x 10^4 J.
Answer:
Explanation:
We shall apply Ampere's circuital law to find out magnetic field . It is given as follows.
∫B.dl = μ₀ I , B is magnetic field , I is current , μ₀ is permeability .
Radius of the wire r = 1.2 x 10⁻³ m
magnetic field B will be circular in shape around the wire. If B is uniform
∫B.dl = B x 2πr
B x 2πr = μ₀ I
B = μ₀ I / 2πr
= 4π x 10⁻⁷ x 37 /2πx1.2 x 10⁻³
= 10⁻⁷ x 2x37 / 1.2 x 10⁻³
= 61.67 x 10⁻⁴ T
= 62 x 10⁻⁴ T
The correct answer is:
<span>The rate at which a waves energy flows through a given unit of area
In fact, light intensity is defined as the light power per unit of area:
</span>
<span>but the power is the energy carried by the light per unit of time:
</span>
<span>this means that the intensity can be rewritten as
</span>
<span>
So, it's basically the rate of energy (per unit of time) through a given surface.</span>