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4 years ago

How many different words can be formed with the letters AAAABBCCD (not necessarily meaningful words)?

Physics

1 answer:

ruslelena [56]4 years ago

5 0

Answer:

90,720 words

Explanation:

The different ways in which a given number of n things or items can be arranged where all of the items are taken at the same time is known as ⁿPₙ which is the same as n factorial, n!

Therefore, the number of alphabets in the word AAAABBCCD = 9

Hence, the number of different words will exclude words where the 4 A, 2 Bs, and 2 Cs are together, and include the number of ways where the the grouped letters can be arranged among themselves as follows

9! × 4! /(4! × 2! × 2!) = 90,720 words

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An 88 kg person steps into a car of mass 2002 kg, causing it to sink 5.36 cm on itssprings. Assuming no damping, with what fre-q

Marina CMI [18]

Answer:

The required frequency = 0.442 Hz

Explanation:

Frequency $f = ( \dfrac{1}{2 \pi}) \omega$

where;

$\omega = \sqrt{\dfrac{k}{m} }$

Then;

$f = \Bigg ( \dfrac{1}{2 \pi} \Bigg ) \Bigg( \sqrt{\dfrac{k}{m} } \Bigg )$

However;

$k = \dfrac{F}{x}$ and;

mass $m = m_{car } + m_{person}$

$f = \Bigg ( \dfrac{1}{2 \pi} \Bigg ) \Bigg( \sqrt{\dfrac{\dfrac{F}{x}}{m_{car}+m_{person}} } \Bigg )$

$f = \Bigg ( \dfrac{1}{2 \pi} \Bigg ) \Bigg( \sqrt{\dfrac{{F}}{x(m_{car}+m_{person})} } \Bigg )$

where;

$F = m_{person}g$

Then;

$f = \Bigg ( \dfrac{1}{2 \pi} \Bigg ) \Bigg( \sqrt{\dfrac{ {m_{person}g }}{x(m_{car}+m_{person})} } \Bigg )$

replacing the values;

$f = \Bigg ( \dfrac{1}{2 \pi} \Bigg ) \Bigg( \sqrt{\dfrac{ {(88 \ kg)* (9.81 \ m/s^2) }}{(5.36 \times 10^{-2} \ m) (2002 \ kg +88 \ kg)} } \Bigg )$

$\mathbf{f = 0.442 \ Hz}$

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3 years ago

A circular loop of radius 11.7 cm is placed in a uniform magnetic field. (a) If the field is directed perpendicular to the plane

Mama L [17]

Answer:

Magnetic field, B = 0.199 T

Explanation:

It is given that,

Radius of circular loop, r = 11.7 cm = 0.117 m

Magnetic flux through the loop, $\phi=8.6\times 10^{-3}\ T/m^2$

The magnetic flux linked through the loop is :

$\phi=B.A$

$\phi=BA\ cos\theta$

Here, $\theta=0$

$B=\dfrac{\phi}{A}$

$B=\dfrac{\phi}{\pi r^2}$

$B=\dfrac{8.6\times 10^{-3}}{\pi (0.117 )^2}$

B = 0.199 T

So, the strength of the magnetic field is 0.199 T. Hence, this is the required solution.

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3 years ago

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pashok25 [27]

When the contracting gas and dust from nebula become so dense and hot that nuclear fusion starts

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4 years ago

Represent a vector of 100 N in North-East direction

andreyandreev [35.5K]

Answer:

please find the attachment to this question.

Explanation:

In this question, we represent the 100N in the North-East direction, but first, we define the vector representation:

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Please find the attachment:

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3 years ago

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lesantik [10]

In this question, one has to carefully understand that the total number of hours in the day can never be more that 24 hours. based on this important fact the answer to the question can be very easily deduced. The only requirement is calculating perfectly.
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4 years ago