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labwork [276]
3 years ago
15

Consider the reaction. At equilibrium, the concentrations of the different species are as follows. [NH3] = 0.105 M [N2] = 1.1 M

[H2] = 1.50 M What is the equilibrium constant for the reaction at this temperature?
Chemistry
1 answer:
Zina [86]3 years ago
4 0

Hey there!:

The reaction is as follows:

N2(g)+ 3 H2(g) ⇌ 2 NH3(g)

At equilibrium, the concentrations of the different species are as follows.:

[NH3] = 0.105 M

[N2] = 1.1 M

[H2] = 1.50 M

The equilibrium constant for the reaction is given as follows:

Keq = [NH3]² / [N2] [H2]³

Keq = (0.105)² / [1.1] [1.50]³

Keq = 0.00296 or 0.0030

The equilibrium constant for the reaction at this temperature is 0.0030.


Hope that helps!

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Silver sulfate (Ag2SO4) is slightly soluble in water and it partly dissolves at the equilibrium according to the following balan
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⇒ S' = 0.0152 mol/L * ( 311.799 g/mol )

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The correct answer is a
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How much 2.0 M NH4NO3 is needed to make 0.585 L of 1.2 M NH4NO3 solution?
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Answer:

b . 0.351 L.

Explanation:

Hello!

In this case, since diluted solutions are prepared by adding an extra amount of diluent to a stock-concentrated solution, we infer that the number of moles of solute remains the same, therefore we can write:

C_1V_1=C_2V_2

Thus, solving for the volume of the stock solution, V1, we obtain:

V_1=\frac{C_2V_2}{C_1}

Now, by plugging in the given data we obtain:

V_1=\frac{1.2M*0.585L}{2.0M}\\\\V_1=0.351L

Therefore, the answer is b . 0.351 L.

Best regards!

5 0
2 years ago
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