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labwork [276]
3 years ago
15

Consider the reaction. At equilibrium, the concentrations of the different species are as follows. [NH3] = 0.105 M [N2] = 1.1 M

[H2] = 1.50 M What is the equilibrium constant for the reaction at this temperature?
Chemistry
1 answer:
Zina [86]3 years ago
4 0

Hey there!:

The reaction is as follows:

N2(g)+ 3 H2(g) ⇌ 2 NH3(g)

At equilibrium, the concentrations of the different species are as follows.:

[NH3] = 0.105 M

[N2] = 1.1 M

[H2] = 1.50 M

The equilibrium constant for the reaction is given as follows:

Keq = [NH3]² / [N2] [H2]³

Keq = (0.105)² / [1.1] [1.50]³

Keq = 0.00296 or 0.0030

The equilibrium constant for the reaction at this temperature is 0.0030.


Hope that helps!

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