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slavikrds [6]
3 years ago
7

Three students derive the following equations in which x refers to distance traveled, v the speed, a the acceleration (m/s^2), a

nd t the time, and the subscript (0) means a quantity at time t=0: a) x=vt^2 + 2at, b) x=v0t+1/2at^2, and c) x=v0t+2at^2. Which of these could possibly be correct according to a dimensional check?
Physics
1 answer:
Lynna [10]3 years ago
3 0

Answer:

B) and C)

Explanation:

Dimensional check involves using the units of the fundamental quantities, like mass to verify the accuracy of a formula or model.

For this case, the quantities required are Length and Time. Their units are Metre (m) and Seconds (s) respectively.

Since x refers to Distance, v refers to velocity, a refers to acceleration and t refers to time,

A) x = vt² + 2at

=> m = (m/s * s²) + (m/s² * s)

m = ms + m/s

The units are unbalanced, hence, it is not dimensionally correct.

B) x = v₀t + 2at²

=> m = (m/s * s) + (m/s² * s²)

m = m + m

The units are balanced, hence, it is dimensionally correct.

C) x = v₀t + ¹/₂at²

=> m = (m/s * s) + (m/s² * s²)

m = m + m

The units are balanced, hence, it is dimensionally correct.

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Given data in the problem :-

  • Acceleration (a) = 4.0 m/s^2
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From Newton's Laws of Motion we know that ,

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4 0
2 years ago
While running, a person dissipates about 0.60 J of mechanical energy per step per kilogram of body mass. If a 68 kg person devel
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Answer:

Speed = 2.25 m/s

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First of all, we would determine the total mechanical energy being dissipated by the person.

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If a = 23 and b = 45

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