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Bess [88]
3 years ago
6

What is the terminal velocity of blood? A. 8.9 feet/seconds B. 9.8 feet/seconds C. 25.1 feet/second D. 52.1 feet/seconds

Physics
1 answer:
goblinko [34]3 years ago
3 0

Answer:

the answer is c) 25.1 feet/second

Explanation:

because the blood droplets can not increase speed past terminal velocity 100.

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1. Which of the following is not an example of friction?
mario62 [17]

ueirudjrufu rhfyrhfy. fur dhrbrhfbf

8 0
3 years ago
A 200-Ω resistor is connected in series with a 10-µF capacitor and a 60-Hz, 120-V (rms) line voltage. If electrical energy costs
Vika [28.1K]

Answer:

Cost to leave this circuit connected for 24 hours is $ 3.12.

Explanation:

We know that,

\mathrm{X}_{\mathrm{c}}=\frac{1}{2 \pi \mathrm{fc}}

f = frequency (60 Hz)

c= capacitor (10 µF = 10^-6)  

\mathrm{X}_{\mathrm{c}}=\text { Capacitive reactance }

Substitute the given values

\mathrm{X}_{\mathrm{c}}=\frac{1}{2 \times 3.14 \times 10 \times 10^{-6} \times 60}

\mathrm{X}_{\mathrm{c}}=\frac{1}{3.768 \times 10^{-3}}

\mathrm{x}_{\mathrm{c}}=265.39 \Omega

Given that, R = 200 Ω

X^{2}=R^{2}+X c^{2}

X^{2}=200^{2}+265.39^{2}

X^{2}=40000+70431.85

X^{2}=110431.825

x=\sqrt{110431.825}

X = 332.31 Ω

\text { Current }(I)=\frac{V}{R}

\text { Current }(I)=\frac{120}{332.31}

Current (I) = 0.361 amps

“Real power” is only consumed in the resistor,  

\mathrm{I}^{2} \mathrm{R}=0.361^{2} \times 200

\mathrm{I}^{2} \mathrm{R}=0.1303 \times 200

\mathrm{I}^{2} \mathrm{R}=26.06 \mathrm{Watts} \sim 26 \mathrm{watts}

In one hour 26 watt hours are used.

Energy used in 54 hours = 26 × 24 = 624 watt hours

E = 0.624 kilowatt hours

Cost = (5)(0.624) = 3.12  

3 0
3 years ago
When starting a foot race, a 64 kilogram sprinter exerts an average force of 693 newtons backward on the ground for 0.59 seconds
cluponka [151]

The distance traveled by the sprinter in meters is determined as 1.88 m.

<h3>Acceleration of the sprinter</h3>

The acceleration of the sprinter is the rate of change of velocity of the sprinter with time.

The acceleration of the sprinter is calculated as follows;

Apply Newton's second law of motion as follows;

F = ma

a = F/m

where;

  • F is the applied force by the sprinter
  • m is mass of the sprinter
  • a is acceleration of the sprinter

a = 693 N / 64 kg

a = 10.83 m/s²

<h3>Distance traveled by the sprinter</h3>

The distance traveled by the sprinter is calculated as follows;

s = ut + ¹/₂at²

where;

  • u is initial velocity = 0

s = ¹/₂at²

where;

  • t is time of motion
  • a is acceleration

s = (0.5)(10.83)(0.59²)

s = 1.88 m

Thus, the distance traveled by the sprinter in meters is determined as 1.88 m.

Learn more about distance here: brainly.com/question/2854969

#SPJ1

6 0
2 years ago
When a brick is dropped from the roof of a house, it lands on the ground with a speed v. What will the speed at ground level be
Nina [5.8K]
Twice as much by the first brick
4 0
3 years ago
How does water affect the coastal climate?
JulijaS [17]
Large bodies of water<span> such as oceans, seas, and large lakes </span>affect<span> the </span>climate<span> of an area. </span>Water<span> heats and cools more slowly than land. Thus, in the summer, the </span>coastal<span> regions </span>will<span> stay cooler and in winter warmer. A more moderate </span>climate<span> with a smaller temperature range </span>is<span> created.</span>
7 0
4 years ago
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