Answer:
C.) 2,1,2
Explanation:
You have to balance the equation by getting the number of elements on the left and right side to equal. Before balancing there is one more oxygen on the left side than the right side. You have to change the coefficient in front of H2O to fix this, and that means adding a "2" in front of the H2 to get that to equal as well.
You end up with 2H₂+10₂→ 2H₂O
Answer:
you're a strong person so keep on keeping on.
Explanation:
Answer:
I believe the answer is C. difficile but to be honest I don't know for sure
Answer:
.................................................
The balanced equation for the above reaction is as follows;
2Ca + O₂ ---> 2CaO
stoichiometry of Ca to O₂ is 2:1
we first need to find the limiting reactant
number of Ca moles - 6.84 mol
number of O₂ moles - 4.00 mol
if Ca is the limiting reactant
if 2 mol of Ca reacts with 1 mol of O₂
then 6.84 mol of Ca reacts with - 6.84 / 2 = 3.42 mol of O₂
this means that Ca is the limiting reactant and O₂ is in excess
therefore amount of CaO produced depends on amount of limiting reactant present
stoichiometry of Ca to CaO is 2:2
number of moles of Ca reacted = number of CaO moles formed
number of moles of CaO formed - 6.84 mol
answer is 6.84 mol