Answer:
2,100J
Explanation:
Workdone=Force x distance
=700 x 3
=2,100 J
GPE = mgh (for objects close to earth where g can be considered to be constant) Where m is the mass, g is the acceleration due to gravity (which the question has told us to assume is 10ms^-2), and h is the height of the object.
Substituting the values in:
GPE = 70*10*10 = 7000J
Velocity units =m/s
Acceleration is the rate of change of velocity
a =timechange in velocity
Therefore SI units of acceleration is ms−1/s=s2m
I think the answer is significant
