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lakkis [162]
4 years ago
7

Consider the following system, which is at equilibrium, 3C(s) + 3H2(g) <--> CH4(g) + C2H2(g) The result of removing some C

(s) from the system will be:
Chemistry
1 answer:
Harrizon [31]4 years ago
4 0

Answer:

The equilibrium position will shift to the left, thus, favouring the backward reaction.

Explanation:

The equation for the reaction is given below:

3C(s) + 3H2(g) <==> CH4(g) + C2H2(g)

According to Le Chatelier's principle, if an external constrain such as change in concentration, temperature or pressure is imposed on a chemical system in equilibrium, the equilibrium will shift in order to neutralize the effect.

From Le Chatelier's principle, removing some C(s) implies removing some of the concentration of the reactants.

This will shift the equilibrium position to the left, thus, favouring the backward reaction (i.e forming more reactants) because removing C(s) implies that the products are now more than the reactants and as such, they will react to form more reactants.

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6 0
4 years ago
Which element causes burning when me mix it with oxygen
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7 0
3 years ago
2C3H6O + 8O2 --&gt; 6CO2 + 6H2O
grigory [225]

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Explanation:

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C_3H_6O is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

According to stoichiometry :

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Thus 0.45 moles of H_2O will be produced from 0.15 moles of propanol.

7 0
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How does the chemical formula for the sulfite ion differ from the chemical formula for the sulfate ion?
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Explanation:

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