A spring that obeys Hooke's law has a spring force constant of 272 N/m. This spring is then stretched by 28.6 cm
Answer:
They will meet at a distance of 7.57 m
Given:
Initial velocity of policeman in the x- direction, 
The distance between the buildings, 
The building is lower by a height, h = 2.5 m
Solution:
Now,
When the policeman jumps from a height of 2.5 m, then his initial velocity, u was 0.
Thus
From the second eqn of motion, we can write:


t = 0.707 s
Now,
When the policeman was chasing across:


The distance they will meet at:
9.57 - 2.0 = 7.57 m
Answer:
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Explanation:
Answer:
velocity of girl with respect to surface of ice 1.154 m/s
Explanation:
Plank Mass , M = 150 kg
Girl Mass , m = 45 kg
velocity of the girl with resect to plank, v1 = 1.50 m/s
velocity of the plank + girl = v2
from the conservation of momentum
Momentum (plank+girl) = - momentum of the girl
(M+m)v2 = -mv1
v2 = -(45 kg)/(195 kg) * 1.50
v2 = -0.346 m/s
velocity of girl with respect to surface of ice =
v1+v2 = 1.50 + (-0.346) = 1.154 m/s