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3 years ago

What is the formula for the Ksp of Fe(OH)3 ? Use the equation mc011-1.jpg

1 answer:

4 0

Ksp, the product of solubility constant is given by the product of the concentrations in the equilibrium of the species on the right hand of the equillibrium reaction, each raised to a power that is its coeffiicient in the equillibrium reaction.

So you must start by writing the equilibrium reaction:

Fe(OH)3 (s) ----> Fe(3+) aq + 3 (OH-) aq

Now you can state the formula for the Ksp

=> Ksp = [Fe (3+) aq] [OH-]^3

So, the answer is the third option of the list.

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2 years ago

23.5 L of h2 is stored at a pressure of 58.7 Kpa what volume would the gas take up at stp

stepan [7]

Answer:- 13.6 L

Solution:- Volume of hydrogen gas at 58.7 Kpa is given as 23.5 L. It asks to calculate the volume of hydrogen gas at STP that is standard temperature and pressure. Since the problem does not talk about the original temperature so we would assume the constant temperature. So, it is Boyle's law.

Standard pressure is 1 atm that is 101.325 Kpa.

Boyle's law equation is:

$P_1V_1=P_2V_2$

From given information:-

$P_1$ = 58.7 Kpa

$V_1$ = 23.5 L

$P_2$ = 101.325 Kpa

$V_2$ = ?

Let's plug in the values and solve it for final volume.

$58.7Kpa*23.5L=101.325Kpa*V_2$

On rearranging the equation for $V_2$

$V_2=\frac{58.7Kpa*23.5L}{101.325Kpa}$

$V_2$ = 13.6 L

So, the volume of hydrogen gas at STP for the given information is 13.6 L.

3 0

2 years ago

Are those correct if not tell me which are wrong I need help with number 21 also

adelina 88 [10]

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3 0

3 years ago

Read 2 more answers

What is the molarity of a solution that contains 200. 0 g of lithium chloride in 450 mL? molar mass of chloride= 42. 394g/mol

alisha [4.7K]

Explanation:

Sol. 450 ml there is LiCl 200 g

Sol. 1000 ml there is LiCl 200/450×1000

= 444.44 g

Molar = g/molar mass = 444.44/42.394 = 10.48 M

3 0

2 years ago

How many atoms are in 52.3 g of lithium hypochlorite (LiClO)?

garri49 [273]

Answer:

1.62 × 10²⁴ atoms are in 52.3 g of lithium hypochlorite.

Explanation:

To find the amount of atoms that are in 52.3 g of lithium hypochlorite, we must first find the amount of moles. We do this by dividing by the molar mass of lithium hypochlorite.

52.3 g ÷ 58.4 g/mol = 0.896 mol

Next we must find the amount of formula units, we do this be multiplying by Avagadro's number.

0.896 mol × 6.02 × 10²³ = 5.39 × 10²³ f.u.

Now to get the amount of atoms we can multiply the amount of formula units by the amout of atoms in one formula unit.

5.39 × 10²³ f.u. × 3 atom/f.u. = 1.62 × 10²⁴ atoms

1.62 × 10²⁴ atoms are in 52.3 g of lithium hypochlorite.

7 0

2 years ago