Answer:
80.27%
Explanation:
Let's consider the following balanced equation.
2 Fe³⁺(aq) + Sn²⁺(aq) ⇒ 2Fe²⁺(aq) + Sn⁴⁺(aq)
First, we have to calculate the moles of Sn²⁺ that react.
![\frac{0.1015molSn^{2+} }{1L} .13.28 \times 10^{-3} L=1.348\times 10^{-3}molSn^{2+}](https://tex.z-dn.net/?f=%5Cfrac%7B0.1015molSn%5E%7B2%2B%7D%20%7D%7B1L%7D%20.13.28%20%5Ctimes%2010%5E%7B-3%7D%20L%3D1.348%5Ctimes%2010%5E%7B-3%7DmolSn%5E%7B2%2B%7D)
We also know the following relations:
- According to the balanced equation, 1 mole of Sn²⁺ reacts with 2 moles of Fe³⁺.
- 1 mole of Fe³⁺ is oxidized from 1 mole of Fe.
- The molar mass of Fe is 55.84 g/mol.
Then, for 1.348 × 10⁻3 moles of Sn²⁺:
![1.348\times 10^{-3}molSn^{2+}.\frac{2molFe^{3+} }{1molSn^{2+} } .\frac{1molFe}{1molFe^{3+} } .\frac{55.84gFe}{1molFe} =0.1505gFe](https://tex.z-dn.net/?f=1.348%5Ctimes%2010%5E%7B-3%7DmolSn%5E%7B2%2B%7D.%5Cfrac%7B2molFe%5E%7B3%2B%7D%20%7D%7B1molSn%5E%7B2%2B%7D%20%7D%20.%5Cfrac%7B1molFe%7D%7B1molFe%5E%7B3%2B%7D%20%7D%20.%5Cfrac%7B55.84gFe%7D%7B1molFe%7D%20%3D0.1505gFe)
If there are 0.1505 g of Fe in a 0.1875 g sample, the mass percentage of Fe is:
![\frac{0.1505g}{0.1875g} \times 100 \% = 80.27\%](https://tex.z-dn.net/?f=%5Cfrac%7B0.1505g%7D%7B0.1875g%7D%20%5Ctimes%20100%20%5C%25%20%3D%2080.27%5C%25)
Mass is not conserved in chemical reactions. Mass is therefore never conserved because a little of it turns into energy in every reaction
Answer:
its a chemical formula, it has numbers and symbols
I'm not sure how many sign fig's you are required to have.
However I think the final answer would be 0.05 Moles, because of the .5g, that is considered 1 sign fig.
Answer:
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Explanation:
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