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3 years ago

What is the formula for the Ksp of Fe(OH)3 ? Use the equation mc011-1.jpg

1 answer:

4 0

Ksp, the product of solubility constant is given by the product of the concentrations in the equilibrium of the species on the right hand of the equillibrium reaction, each raised to a power that is its coeffiicient in the equillibrium reaction.

So you must start by writing the equilibrium reaction:

Fe(OH)3 (s) ----> Fe(3+) aq + 3 (OH-) aq

Now you can state the formula for the Ksp

=> Ksp = [Fe (3+) aq] [OH-]^3

So, the answer is the third option of the list.

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Why do particles settle down in suspension

fomenos

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6 0

3 years ago

A closed system initially containing 1×10^-3 hydrogen 2×10^-3M iodine at 448 degree Celsius and is allowed to reach equilibrium.

GaryK [48]

Answer:

Kc = 50.5

Explanation:

We determine the reaction:

H₂ + I₂ ⇄ 2HI

Initially we have 0.001 molesof H₂

and 0.002 moles of I₂

If we have produced 0.00187 moles of HI in the equilibrium we have to know, how many moles of I₂ and H₂, have reacted.

H₂ + I₂ ⇄ 2HI

In: 0.001 0.002 -

R: x x 2x

Eq: 0.001-x 0.002-x 0.00187

x = 0.00187/2 = 9.35×10⁻⁴ moles that have reacted

So in the equilibrium we have:

0.001 - 9.35×10⁻⁴ = 6.5×10⁻⁵ moles of H₂

0.002 - 9.35×10⁻⁴ = 1.065×10⁻³ moles of I₂

Expression for Kc is = (HI)² / (H₂) . (I₂)

0.00187 ² / 6.5×10⁻⁵ . 1.065×10⁻³ = 50.5

5 0

3 years ago

If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the of strontium-90 is ________ yr.

lesantik [10]

The question is incomplete, here is the complete question.

If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the half-life of strontium-90 is ________ yr.

a. 28.8 b. 30.9 c. 35.4 d. 32.2

Answer : The half-life of strontium-90 is 28.8 years.

Explanation :

This is a type of radioactive decay and all radioactive decays follow first order kinetics.

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by :

$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

k = rate constant

t = time taken for decay process = 9.00 year

a = initial amount or moles of the reactant = 1.000 g

a - x = amount or moles left after decay process = 0.805 g

Putting values in above equation, we get:

$k=\frac{2.303}{9.00}\log\frac{1.00}{0.805}$

$k=0.0241\text{ year}^{-1}$

To calculate the half-life, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$0.0241\text{ year}^{-1}=\frac{0.693}{t_{1/2}}$

$t_{1/2}=28.8\text{ years}$

Therefore, the half-life of strontium-90 is 28.8 years.

5 0

3 years ago

What volume of 0. 250 m sulfuric acid solution would be needed to react completely with 18. 00 ml of 0. 350 m ammonia solution?

PolarNik [594]

The volume of 0. 250 m sulfuric acid solution would be needed to react completely with 18. 00 ml of 0. 350 m ammonia solution is 0.0504 L.

The balance reaction is 2KOH+ $H_{2} SO_{4}$ = $2H_{2} O+K_{2} SO_{4}$

This shows us that we need 2 moles of KOH for each mole of sulfuric acid.

So, we write mathematically 2*(0.018*0.350)=(V*0.250)

V=(2*0.018*0.350)/0.250=0.0504 L

<h3>Sulfuric acid</h3>

With the chemical formula H2SO4, sulfuric acid, also known as sulphuric acid or oil of vitriol, is a mineral acid made up of the elements hydrogen, oxygen, and sulfur. It is a viscous liquid that is miscible with water and is colorless, odorless, and viscous.

Since pure sulfuric acid has a significant affinity for water vapor, it does not naturally occur on Earth; as a result, it is hygroscopic and rapidly collects water vapor from the atmosphere. Due to its potent dehydrating and oxidizing qualities, concentrated sulfuric acid is extremely corrosive to various materials, including rocks and metals. One significant exception is phosphorus pentoxide, which dehydrates sulfuric acid to sulfur trioxide instead of being dehydrated by sulfuric acid.

Learn more about Sulfuric acid here:

brainly.com/question/1107054

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6 0

2 years ago

Container A holds 717 mL of ideal gas at 2.50 bar . Container B holds 179 mL of ideal gas at 4.30 bar . If the gases are allowed

Nesterboy [21]

Answer:

Pressure gas A

using boyles law

$p1}$ $V_{1}$ = $P_{2}$ V2

V2 = 717ml + 179 ml

= 896ml

∴ $P_{2}$ = 2.50 × 717ml/896ml

= 2.0 bar

Pressure B

P2 = 4.30 bar× 179ml/896ml

= 0.859bar

ptotal = $P_{A}$ + $P_{B}$

= 2.0 bar + 0.859 bar

= 2.859 bar

Explanation: Using Daltons law of partial pressure,the pressure is independently of each other when the gas is exerted.where we can use daltons law to find the pressure of each gas separately when it expands into the total volume in two containers.

7 0

3 years ago