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Andrej [43]
3 years ago
14

What is the formula for the Ksp of Fe(OH)3 ? Use the equation mc011-1.jpg

Chemistry
1 answer:
zhenek [66]3 years ago
4 0
Ksp, the product of solubility constant is given by the product of the concentrations in the equilibrium of the species on the right hand of the equillibrium reaction, each raised to a power that is its coeffiicient in the equillibrium reaction.

So you must start by writing the equilibrium reaction:

Fe(OH)3 (s) ----> Fe(3+) aq  +   3 (OH-) aq

Now you can state the formula for the Ksp

=> Ksp = [Fe (3+) aq] [OH-]^3

So, the answer is the third option of the list.
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Artemon [7]

Explanation:

b. Bromo cyclopentane + HBr

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2 years ago
When collecting your solid, why should the filter paper in the Buchner funnel be wetted with some of the cold recrystallization
Mnenie [13.5K]

Answer:   It is important to wet the filter paper in the Buchner funnel first with cold re crystallization solvent before the re crystallization mixture being filtered to minimize gaps around the edges of the filter paper which can prevent mechanical impurities from passing through. This gives better filtration where most impurities can be filtered. Furthermore, it provides good vacuum.

6 0
3 years ago
(4) Calculate the % of a compound that can be removed from liquid phase 1 by using ONE to FOUR extractions with a liquid phase 2
maksim [4K]

Answer:

One extraction: 50%

Two extractions: 75%

Three extractions: 87.5%

Four extractions: 93.75%

Explanation:

The following equation relates the fraction q of the compound left in volume V₁ of phase 1 that is extracted n times with volume V₂.

qⁿ = (V₁/(V₁ + KV₂))ⁿ

We also know that V₂ = 1/2(V₁) and K = 2, so these expressions can be substituted into the above equation:

qⁿ = (V₁/(V₁ + 2(1/2V₁))ⁿ = (V₁/(V₁ + V₁))ⁿ =  (V₁/(2V₁))ⁿ = (1/2)ⁿ

When n = 1, q = 1/2, so the fraction removed from phase 1 is also 1/2, or 50%.

When n = 2, q = (1/2)² = 1/4, so the fraction removed from phase 1 is (1 - 1/4) = 3/4 or 75%.

When n = 3, q = (1/2)³ = 1/8, so the fraction removed from phase 1 is (1 - 1/8) = 7/8 or 87.5%.

When n = 4, q = (1/2)⁴ = 1/16, so the fraction removed from phase 1 is (1 - 1/16) = 15/16 or 93.75%.

5 0
3 years ago
A piece of metal with a mass of 150 g is placed in a 50 mL graduated cylinder. The water level rises from 20 mL to 45mL. What is
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Answer:

25 mL

Explanation:

The water level increased from 20mL to 45mL

That is the volume of the metal

45 - 20 = 25

The volume of the metal was 25 mL

Density = mass / volume

Density = 150 / 25

Density = 6 grams / mL

7 0
3 years ago
The diagram shows one period of the Periodic Table. Li ,Be ,B , C,N,O,F,Ne .Which two elements form acidic oxides?
Rudik [331]

Answer:

A -carbon and lithium.

Explanation:

6 0
1 year ago
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