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3 years ago

How many hydrogen atoms are in 5.80 mol of ammonium sulfide

Chemistry

1 answer:

IRINA_888 [86]3 years ago

5 0

Moles of ammonium sulfide = 5.80 mol

The formula of ammonium sulfide is (NH₄)₂S

So each molecule of ammonium sulfide has (4 x 2) or 8 atoms of H

One mole of ammonium sulfide has 8 moles of H

5.80 mol of ammonium sulfide has (8 x 5.8) or 46.4 moles of H

As per the definition of Avogadro's number, 1 mole = 6.022 x 10²³ atoms

46.4 moles of H x (6.022 x 10²³ atoms/ 1 mole of H)

= 2.8 x 10²⁵ H atoms

Therefore, 2.8 x 10²⁵ H atoms are in 5.80 mol of ammonium sulfide.

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Answer:

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Explanation:

Given

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According to the first law of thermodynamics

In the question, it can be observed that the volume of the reactor is unaltered

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The Internal energy to keep the tank's constant temperature is given as

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∆U = Cv((45 + 273) - (25 + 273))

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Before calculating the heat loss of the tank, we must first calculate the amount of moles of gas that entered the tank where P1 = 101.33 kPa

The Initial mole is calculated as

(P * V)/(R * T)

Where P = P1 = 101.33kPa = 101330Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

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So, n = (101330 * 0.1)/(8.314*298)

n = 4.089891232222

n = 4.089

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T = Initial Temperature = 25 + 273 = 298K

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n = 60.54314465936812

n = 60.543

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