Answer:
As the temperature of a liquid increases, the kinetic energy of its molecules also increases. As the kinetic energy of the molecules increases, the number of molecules transitioning into a vapor also increases, thereby increasing the vapor pressure.
1) 7.15 * 10^6
since the exponent of the scientific notation is positive, move 6 places to the right.
so, <em>7.15 * 10^6 = 7150000</em>
2) 3.03 * 10^-8
Since the exponent of the scientific notation is negative, move the decimal point 8 places to the left.
so,<em> 3.03 * 10^-8 = 0.0000000303</em>
<em />
3)<em> </em>4.9 * 10^-1
since the exponent of the scientific notation is negative, move 1 decimal place to the left.
so,<em> 4.9 * 10^-1 = 0.49</em>
<em />
4) 2.886 * 10^5
since the exponent of the scientific notation is positive, move 5 decimal places to the right.
so,<em> 2.886 * 10^5 = 288600</em>
We know that molarity = mol/L, so:
1.5 M = x mol/0.345 L
1.5 M * 0.345 L = x mol => 0.5175 mol
0.5175 mol/0.250 L = 2.07 M
Your new molarity of the solution will be 2.07 M.
The enthalpy of combustion of 1 mole of benzene is 3169 kJ/mol .
The first step in answering this question is to obtain the balanced thermochemical equation of the reaction. The thermochemical equation shows the amount of heat lost or gained.
The thermochemical equation for the combustion of benzene is;
2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) ΔrH° = -3169 kJ/mol
We can see that 1 mole of benzene releases about 3169 kJ/mol of heat.
Learn more: brainly.com/question/13164491
Answer:
Reagent A: PBr₃
Reagent B: Mg in Et₂O.
Explanation:
Hello,
In this case, your facing a problem in which a carboxylic acid is produced starting by an alcohol. More specifically, cyclopentanol must react with phosphorous tribromide in order to yield bromocyclopentane which is more likely to produce a carboxylic acid, therefore, reagent A is PBr₃.
On the other hand, by means of the production of the specified product, bromocyclopentane must react with carbon dioxide and magnesium in diethyl ether in acidic media to promote the production of the cyclopentanoic acid via the grignard reaction (substitution of the bromine by the carboxyle group), therefore, reagent B is Mg in Et₂O.
Best regards.
