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Andreyy89
3 years ago
14

Zinc + Hydrochloric Acid → Zinc Chloride and Hydrogen Gas

Chemistry
2 answers:
Kipish [7]3 years ago
3 0

Explanation:

because in the right side there is 2 hydrogen( H) and 2 chloride (Cl) to balace them we have to replace 2.

Kruka [31]3 years ago
3 0

Answer:

This is because you need the same amount of atoms on each side and when you go to the reaction side you see that by adding the coefficient in from the H, 2, the hydrogen and chlorine react to make HCI :))

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Potassium impart purple colour but beryllium do not impart any colour to the flame.Why?​
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Answer:

<h2>The electrons in beryllium and magnesium are too strongly bound to get excited by flame. Hence, these elements do not impart any color.</h2>
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The state of water is determined solely by the conditions of _____.
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Balance the following chemical equations
jok3333 [9.3K]

Answer:

2N2 + O2 ⇒ 2N2O

Explanation:

Since I cannot see the product's of the second chemical equation I will only solve the first one.

In order to balance a chemical equation you need to make sure that the atoms on both sides are equal.

In this case we have...

N2 + O2 = N2O

N = 2

O = 2

N = 2

O = 2

Change the coefficient:

N2O = 2N20

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1 × 2 = 2

2N2 + O2 ⇒ 2N2O

Hope this helps.

4 0
2 years ago
What will be the volume of a gas sample at 358 K if its volume at 255 K is 7.4 L?
Jobisdone [24]

Answer:

10.4 L

Explanation:

V1/T1=V2/T2

V2= (V1*T2)/T1

V2= (7.4L * 358K)/255K

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4 0
3 years ago
A chemist makes 940. mL of sodium carbonate (Na_2CO_3) working solution by adding distilled water to 200. mL of a 0.171 m stock
Alexxandr [17]

Answer:

The answer is 0.0698 M

Explanation:

The concentration was prepared by a serial dilution method.

The formula for the preparation I M1V1 = M2V2

M1= the concentration of the stock solution = 0.171 M

V1= volume of the stock solution taken = 200 mL

M2 = the concentration produced

V2 = the volume of the solution produced = 940 mL

Substitute these values in the formula

0.171 × 200 = 490 × M2

34.2 = 490 × M2

Make M2 the subject of the formula

M2 = 34.2/490

M2 = 0.069795

M2 = 0.0698 M ( 3 s.f)

The concentration of the Chemist's working solution to 3 significant figures is 0.0698M

6 0
3 years ago
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