<h2>
Answer:7.14
,4.125</h2>
Explanation:
Whenever an object is moving in a 2D frame,its motion can be analysed as if it is travelling in two independent 1D frames.
One of such independent 1D frames are along horizontal and another along vertical.
Let 
be the total velocity.
Given that,
We call the horizontal velocity as 
and the vertical velocity as 
.
=
where 
is the angle between the object and horizontal.
It is given that 
Answer:
<em>Fx = 121.24lb</em>
<em>F = 140lb</em>
Explanation:
Since we are not given the angles subtended by the force, we can assume it to be 30 degrees.
The y component of the force expressed by the formula:
Fy = Fsintheta
Given the y-component of the force F to bee 70lb
70lb = Fsintheta
Get magnitude of the force
F = 70/sin theta
F = 70/sin 30
F = 70/0.5
F = 140lb
Get the x-component of the force
Fx = Fcos theta
Fx = 140cos 30
Fx = 140(0.8660)
Fx = 1,212.4lb
<em>Hence the x-component of the force sis 121.24lb</em>
<em></em>
<em>Note that the angle used was assumed. Other values can as well be used</em>
C^2=a^2+b^2
c^2=45^2+45^2
c^2=4050
c=63.64
c=64
The answer is D.
The components that must be present for work to be considered is a force and a movement in the same direction as the force. In the basic definition of work, a magnitude and displacement that occurs in the same direction is what makes up work. Among the choices, the correct answer is the first one.
