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garri49 [273]
4 years ago
11

Give the number of electrons, protons, and neutrons in an atom of Americium-241.

Chemistry
1 answer:
ohaa [14]4 years ago
3 0
Neutrons : 146
Protons : 95
Electrons : 95
You might be interested in
If 20.0 g LIOH react with excess KCl, giving a 17.0
adell [148]

The yield of lithium chloride is 1.92 grams.

Option D.

<h3><u>Explanation:</u></h3>

In this reaction, we can see that 1 mole of lithium hydroxide reacts with 1 mole of potassium chloride to produce 1 mole of lithium chloride and 1 mole of potassium hydroxide.

Molecular weight of lithium hydroxide is 24.

Molecular weight of lithium chloride is 42.5.

So 24 grams of lithium hydroxide produces 42.5 grams of lithium chloride.

So, 20 grams of lithium hydroxide produces 20 * 24 / 42.5  grams =11. 29 grams of lithium chloride.

But this is when the yield is 100%.

But yield is 17%.

So the yield is 1.92 grams of lithium chloride.

8 0
3 years ago
the two stages that take place during distillation are. a.evaporation is folloeed by condensation. b.condensation followed by ev
ValentinkaMS [17]

Answer:

evapiration followed by condensation

3 0
2 years ago
CH4+O2—-CO2+H2O what is the best classification for the unbalanced equations reaction and why
yawa3891 [41]
I don’t know what you mean by classification exactly but it is a redox equation. The reactant side of carbon is losing hydrogen to form carbon dioxide. And oxygen is gaining hydrogen which gives you the water. Redox reactions are also known as combustion reactions.
5 0
3 years ago
If the percent by volume is 2.0% and the volume of solution is 250 mL, what is the volume of solute in solution? Show your work.
Mrrafil [7]
Volume of solute = 250 * 2%
= 250 * 0.02
= 5

In short, Your Answer would be 5 mL

Hope this helps!
3 0
3 years ago
A solution of 2-propanol and 1-octanol behaves ideally. Calculate the chemical potential of 2-propanol in solution relative to t
andrew-mc [135]

Answer:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

Explanation:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol can be calculated using the following equation:

\mu (l) = \mu ^{\circ} (l) + R*T*ln(x)

<u>Where:</u>

<em>μ (l): is the chemical potential of 2-propanol in solution    </em>

<em>μ° (l): is the chemical potential of pure 2-propanol   </em>

<em>R: is the gas constant = 8.314 J K⁻¹ mol⁻¹ </em>

<em>T: is the temperature = 82.3 °C = 355.3 K </em>

<em>x: is the mole fraction of 2-propanol = 0.41 </em>

\mu (l) = \mu ^{\circ} (l) + 8.314 \frac{J}{K*mol}*355.3 K*ln(0.41)

\mu (l) = \mu ^{\circ} (l) - 2.63 \cdot 10^{3} J*mol^{-1}

\mu (l) - \mu ^{\circ} (l) = - 2.63 \cdot 10^{3} J*mol^{-1}  

Therefore, the chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

I hope it helps you!    

8 0
4 years ago
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