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3 years ago

What is the primary cause of diffusion?

Physics

2 answers:

fiasKO [112]3 years ago

8 0

Answer:

Explanation:

Lostsunrise [7]3 years ago

3 0

Answer
c). random internal motion of atoms and molecules.

Explanation 
Diffusion is the movement of particles from a region of high concentration to region of low concentration. The rate of diffusion can be increased by increasing amount of temperature but this is not its primary cause. Diffusion is primarily caused by movement of molecules or atoms in a substances. Form the choices given, the correct answer is c. random internal motion of atoms and molecules.

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Vector A has a magnitude of 8.0 m and points east, vector B has a magnitude of 6.0 m and points north and vector C has a magnitu

sineoko [7]

Answer:

The answer is E) 6.7m at an angle 63° north of east

Explanation:

We begin by writing out our given vectors A,B and C in their respective rectangular Cartesian coordinate form. which are given as A=8i, B=6j and C= -5j (negative because it points towards west which is towards the left which is taken as the negative direction).Now we simply add all three to obtain our final vector given by,

$V=A+B+C\\V=8i + 6j - 5i\\V=3i + 6j$

In the last step we just added the like components. Now we will have to calculate the magnitude and angle of V(with respect of the east direction), which is given by,

$|V| = \sqrt{3^2 + 6^2} =6.7m\\\\\alpha =tan^{-1} (6/3)=tan^{-1} (2) = 63.4$

the angle alpha is always calculated with respect to the horizontal positive axis, and since both components of the vector are positive the vector lies in the first quadrant. Hence the 63° angle north of east is justified. The term north of east means the angle formed in moving from east towards the north that is from the positive horizontal axis to the positive vertical axis.

8 0

4 years ago

#4 HELP PLEASE! Find Gravitational Potential Energy! THANK YOU!

Scilla [17]

Answer:

$\Delta GPE=-3.92\ 10^9\ J$

Explanation:

Gravitational Potential Energy

It's the capacity of an object to do work due to its relative height from a fixed reference point.

It's computed as

GPE=m.g.h

Where m is the mass of the object, h is its height and g is the acceleration of gravity, $g=9.8 m/sec^2$

The mass of water is given as

$m=8,000,000\ kg$

The height above the rocks is h=50 m. Let's compute the GPE

$GPE_1=(8,000,000\ kg)(9.8\ m/s^2)(50\ m)$

$GPE_1=3,920,000,000\ Joule$

It should be expressed in scientific notation

$GPE_1=3.92\ 10^9\ J$

The GPE at the bottom, where h=0

$GPE_2=0$

The change of gravitational potential energy is:

$\Delta GPE=GPE_2-GPE_1$

$\boxed{\Delta GPE=-3.92\ 10^9\ J}$

8 0

3 years ago

The acceleration of gravity on Earth is approximately 10 m/s2 (more precisely, 9.8 m/s2). If you drop a rock from a tall buildin

mars1129 [50]

Answer:

30 m/s

Explanation:

Velocity is $v_{final}=v_{initial}+at$ since we know that the initial velocity is 0, and the acceleration is $9.8 \frac{m}{s^2} \approx 10 \frac{m}{s^2}$ then we also know that time is 3 seconds it follows that: $v_{final}=v_{initial}+at=0+10\frac{m}{s^2}*3s=30\frac{m}{s}$