Question

Comic-book superheroes are sometimes able to punch holes through steel walls. (a) If the ultimate shear strength of steel is taken to be 2.50 x 108 Pa, what force is required to punch through a steel plate 2.00 cm thick? Assume the superhero’s fist has cross-sectional area of 1.00 x 102 cm2 and is approximately circular. (b) Qualitatively, what would happen to the superhero on delivery of the punch? What physical law applies?

Answer 1

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shear stress is the measure of the material's resistance to cause "sliding" motion of its layers. 
Since the hero has to take a cylindrical piece of metal out, the area which will cause this force is 2*pi*r*l (put r and l in SI units to get answer in Newtons) 
so the force required is shear strength into this area (2.60109 * 2 * pi * r * l)