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3 years ago

Compare and contrast tension,compression and extension

1 answer:

8 0

In physical science, tension can be described as the motion that applies a pulling force that is transmitted axially through cables, chains, or string. On the other hand, compression is the application of balanced inward forces while extension is the application of balanced outward forces in the same axis through the object.

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NEED HELP ASAP !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

stepan [7]

Answer:

Electric charge

Like; opposite

Faster

True

positive to negative

Explanation:

6 0

3 years ago

This is important I need to turn this in tomorrow, How many half-lives does it take to get from 1,000 to 125, and in what region

Alekssandra [29.7K]

It takes 3 half-lives:
1. 1000 -> 500
2. 500 -> 250
3. 250 ->125

I'm not sure about the Virginia thing so good luck!

And congratulations on being my first answer-person!!

3 0

4 years ago

Two football players with mass 75kg and 100kg run directly toward each other with speeds of 6 m/s and 8 m/s respectively, If the

Rina8888 [55]

Answer:

2 m/s

Explanation:

From the law of conservation of momentum,

Total momentum before collision = total momentum after collision

mu+m'u' = V(m+m') .................................Equation 1

Where m = mass of the first player, u = initial speed of the first player, m' = mass of the second player, u' = initial speed of the second player, V = combined speed of both players.

Making V the subject of the equation,

V = (mu+m'u')/(m+m')................ Equation 2

Note: Taking the direction of the first player as positive.

Given: m = 75 kg, m' = 100 kg, u = 6 m/s, u' = -8 m/s (opposite the first player),

Substituting into equation 2

V = [(75×6)+(100×(--8))]/(75+100)

V = (450-800)/175

V = 350/175

V = - 2 m/s.

Note: The negative signs tells that the combined speed is in the direction of the second player.

Hence the combined speed of the two players = 2 m/s

8 0

4 years ago

Can someone help check question 2 I don’t think part 2 is right?!

Alisiya [41]

Your answer for question two is right

4 0

3 years ago

Suppose you increase your walking speed from 4m/s to 12m/s in a period of 1 s. What is your acceleration?

den301095 [7]

We use the following formula to determine our acceleration:
$acceleration = \frac{(final velocity) - (initial velocity)}{time} = \frac{change of velocity}{time}$
We normally use letters in this formula, which gives us:
$a = \frac{v}{t}$

Filling in this formula gives us:
Δv (change of velocity) = 12 - 4 = 8 m/s
t = 1s
$a = \frac{8}{1} = 8 m/s^2$
So our answer: the acceleration is $8m/ s^{2}$

3 0

3 years ago