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3 years ago

9

Compare and contrast tension,compression and extension

1 answer:

Semmy [17]3 years ago

8 0

In physical science, tension can be described as the motion that applies a pulling force that is transmitted axially through cables, chains, or string. On the other hand, compression is the application of balanced inward forces while extension is the application of balanced outward forces in the same axis through the object.

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How to the eath turn

mrs_skeptik [129]

Explanation:

Earth rotates in prograde mation.As viewed from the north pole star Polaris.Earth turns counterclockwise,, the north pole is point in the northern,, Hemisphere where Earth's Axis of rotation meets it's surface

5 0

3 years ago

Read 2 more answers

A 120 g, 8.0-cm-diameter gyroscope is spun at 1000 rpm and allowed to precess. What is the precession period?

dolphi86 [110]

To solve this problem we will derive the expression of the precession period from the moment of inertia of the given object. We will convert the units that are not in SI, and finally we will find the precession period with the variables found. Let's start defining the moment of inertia.

$I = MR^2$

Here,

M = Mass

R = Radius of the hoop

The precession frequency is given as

$\Omega = \frac{Mgd}{I\omega}$

Here,

M = Mass

g= Acceleration due to gravity

d = Distance of center of mass from pivot

I = Moment of inertia

$\omega$ = Angular velocity

Replacing the value for moment of inertia

$\Omega= \frac{MgR}{MR^2 \omega}$

$\Omega = \frac{g}{R\omega}$

The value for our angular velocity is not in SI, then

$\omega = 1000rpm (\frac{2\pi rad}{1 rev})(\frac{1min}{60s})$

$\omega = 104.7rad/s$

Replacing our values we have that

$\Omega = \frac{9.8m/s^2}{(8*10^{-2}m)(104.7rad)}$

$\Omega = 1.17rad/s$

The precession frequency is

$\Omega = \frac{2\pi rad}{T}$

$T = \frac{2\pi rad}{\Omega}$

$T = \frac{2\pi}{1.17}$

$T = 5.4 s$

Therefore the precession period is 5.4s

7 0

3 years ago

Can an object be in motion and not in motion at the same time? Explain.

kolezko [41]

It could rotate while not advancing distance

5 0

3 years ago

If two equal charges are separated by a certain distance, the force of repulsion is F. Given F1, if each charge in F1 is doubled

Alisiya [41]

Answer: $F_2=16\times F_1$

Explanation:

Given

Force of repulsion between two charge particle is given by force F

Electrostatic force is given by

$F=\frac{kq_1q_2}{r^2}$

where $q_1$ and $q_2$ is the charges of particle

r=distance between charge particle

$=\frac{kq^2}{r^2}$ when charges are doubled and distance is reduced to half

i.e. q become 2 q and r becomes 0.5 r

$F_2=\frac{k(2q)^2}{(0.5r)^2}$

$F_2=\frac{kq^2}{r^2}\times 4\times 4$

$F_2=16\times F_1$

6 0

3 years ago

10. Ahmad drives 60 km from his house to the petrol station in a car moving at a constant speed of

djyliett [7]

Answer:

Explanation:

Average speed is distance traveled over time taken to do so

home to station

d = 60 km

t = 60 km/60 km/hr = 1 hr

station to shop

d = 60 km

t = 60 km / 120 km/hr = ½ hr

speed

s = (60 + 60) / (1 + ½) = 120/1.5 = 80 km/h

7 0

3 years ago