Answer:
Step-by-step explanation:
Length = x
width = x - 7
height = x - 10
volume = 600 in^3
Volume = L * w * h
600 = x * (x - 7)*(x - 10)
600 = x * (x^2 - 17x + 70)
600 = x^3 - 17x^2 + 70x
x^3 - 17x^2 + 70x - 600 = 0
There is a genius somewhere that could solve this using algebra. The rest of us have 2 choices. We can graph it (see below) or we could use a program that solves it for us. I'll do both for you.
a = 1
b = - 17
c = 70
d = - 600
There is only 1 real solution: x = 15
L = 15
w = 8
h = 5
That has to be one of the ugliest graphs made. It does into the hundreds of thousands and it still looks like a straight line. Trust me. It's not.
Answer: Taxi driver has at most $10 to spend on the cab ride, he can travel at most 12.7 miles.
Step-by-step explanation:
A Taxi driver charges a flat rate = 7.25 dollars
taxi fare for 1 mile = 0.65 dollars
Suppose we consider Total money taxi driver can spend = 10 dollars
Let taxi driver travel x miles
Total charges = flat rate charge + taxi fare for each mile(distance) travelled
Find the value y = [?] + [?]x
suppose these two question marks indicate z1,z2
replace with y=10 and z1=1.75 and z2=0.65 values
Then y = [z1] + [z2]x
10 = 1.75 + 0.65(x)
0.65(x) = 10 - 1.75
0.65(x)= 8.25
x = 8.25/0.65
x = 12.7 miles
If Taxi driver has at most $10 to spend on the cab ride, he can travel at most 12.7 miles.
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The questions is asking which one and i say is graph B
9514 1404 393
Answer:
- ABHGEFDCA
- does not exist
- ECBADFE
Step-by-step explanation:
A Hamiltonian circuit visits each node once and returns to its start. There is no simple way to determine if such a circuit exists.
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For graph 2, if there were a circuit, paths ACB, ADB, and AEB would all have to be on it. Inclusion of all of those requires visiting nodes A and B more than once, so the circuit cannot exist.
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For graph 3, the circuit must include paths BAD and DFE. That only leaves node C, which can be reached from both nodes B and E, so path ECB completes the circuit.
