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2 years ago

The gamma ray released by each decay carries 140kev of energy. find the total energy e released by decays in the 2 hours.

Physics

2 answers:

olya-2409 [2.1K]2 years ago

8 0

First, we would need to know the decaying isotope.
Next, we use the decay formula
A = Ao e^(-kt)
After determining the remaining amount after two hours, the decay reaction can be used to determine the number of gamma rays released. If the given is in terms of mole, then the total energy is
E = 140n KeV where n is the number of moles of gamma rays released

Anestetic [448]2 years ago

6 0

Answer:

Please see attachment

Explanation:

Please see attachment

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A tennis ball of mass 44.0 g is held just above a basketball of mass 594 g. With their centers vertically aligned, both are rele

ZanzabumX [31]

Answer:

u = 4.6 m/s

h = 8.01 m

Explanation:

Given:

Mass of the tennis ball, m = 44.0 g

Mass of the basket ball, M = 594 g

Height of fall, h = 1.08m

Now,

we have

$u^2-u'^2 = 2as$

where, s = distance = h

a = acceleration

u = final speed before the collision

u' = initial speed

since it is free fall case

thus,

a = g = acceleration due to gravity

u' = 0

thus we have

$u^2-0^2 = 2\times9.8\tiimes1.08$

$u = \sqrt{21.168}$

u = 4.6 m/s

b) Now after the bounce, the ball moves with the same velocity

thus, v = v₂

thus,

final speed ( $v_f$ ) = v = 4.6 m/s

Then conservation of energy says

$\frac{1}{2}mu_1^2+\frac{1}{2}Mu_2^2 = \frac{1}{2}mv_1^2+\frac{1}{2}Mv_2^2$

also

applying the concept of conservation of momentum

we have

mu₁ + Mu₂ = mv₁ + Mv₂

u₁ =velocity of the tennis ball before collision = -4.6 m/s

u₂ = velocity of the basketball before collision= 4.6 m/s

v₁ = velocity of the tennis ball after collision

v₂ = velocity of the basketball after collision

substituting the values in the equation, we get

Now,

solving both the equations simultaneously we get

$v = (\frac{2M}{m+M})u_1+(\frac{m-M}{m+M})u_2$

substituting the values in the above equation we get

$v = (\frac{2\times594}{44+594})(-4.6)+(\frac{44-594}{44+594})4.6$

$v = -8.565-3.965$

$v = -12.53m/s$

here negative sign depicts the motion of the ball in the upward direction

now the kinetic energy of the tennis ball

$K.E = \frac{1}{2}mv^2$

$K.E = \frac{1}{2}44\times 10^{-3}kg\times 12.53^2$

K.E = 3.45 J

also at the height the K.E will be the potential energy of the tennis ball

thus,

3.45 J = mgh

3.45 = 44 × 10⁻³ × 9.8 × h

h = 8.01 m

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The figure shows the displacement y of a traveling wave at a given position as a function of time and the displacement of the sa

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Wavelength of the wave is 3 m.

<h3>What is Wavelength?</h3>

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to learn more about Wavelength go to - brainly.com/question/10750459

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