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3 years ago

The gamma ray released by each decay carries 140kev of energy. find the total energy e released by decays in the 2 hours.

Physics

2 answers:

olya-2409 [2.1K]3 years ago

8 0

First, we would need to know the decaying isotope.
Next, we use the decay formula
A = Ao e^(-kt)
After determining the remaining amount after two hours, the decay reaction can be used to determine the number of gamma rays released. If the given is in terms of mole, then the total energy is
E = 140n KeV where n is the number of moles of gamma rays released

Anestetic [448]3 years ago

6 0

Answer:

Please see attachment

Explanation:

Please see attachment

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3 years ago

Read 2 more answers

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Answer:

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convert km/h into m/s

v = 18.61 m/s

Let the angle of banking of road is θ, without friction

$tan\theta =\frac{v^{2}}{rg}$

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3 years ago

Question 5 (1 point)

Tom [10]

Answer: 18000 coulombs

Explanation:

Given that:

Current, I = 5.0A

Electric charge Q = ?

Time, T = 1 hour

(The SI unit of time is seconds. So, covert 1.0 hour to seconds)

If 1 hour = 60 minutes and 60 seconds = 1 minute

Then, 1.0 hour = (60 x 60)

= 3600 seconds

Since electric charge, Q = current x time

i.e Q = I x T

Q = 5.0 A x 3600 seconds

Q = 18000 coulombs

Thus, 18000 coulombs of charge flows through the lamp in this time.

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