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AleksandrR [38]
3 years ago
5

The gamma ray released by each decay carries 140kev of energy. find the total energy e released by decays in the 2 hours.

Physics
2 answers:
olya-2409 [2.1K]3 years ago
8 0
First, we would need to know the decaying isotope.
Next, we use the decay formula
A = Ao e^(-kt)
After determining the remaining amount after two hours, the decay reaction can be used to determine the number of gamma rays released. If the given is in terms of mole, then the total energy is
E = 140n KeV where n is the number of moles of gamma rays released
Anestetic [448]3 years ago
6 0

Answer:

Please see attachment

Explanation:

Please see attachment

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Elis [28]

Answer:

   ω = ω₀ + α t

      ω² = ω₀² + 2 α  θ

      θ = θ₀ + ω₀ t + ½ α t²

Explanation:

Rotational kinematics can be treated as equivalent to linear kinematics, for this change the displacement will change to the angular displacement, the velocity to the angular velocity and the acceleration to the angular relation, that is

     x → θ

     v → ω

     a → α

with these changes the three linear kinematics relations change to

      ω = ω₀ + α t

      ω² = ω₀² + 2 α  θ

      θ = θ₀ + ω₀ t + ½ α t²

where it should be clarified that to use these equations the angles must be measured in radians

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2 years ago
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Sergeeva-Olga [200]
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3 years ago
The position of a particle moving along the x axis is given by x = (21 + 22t – 6 t2) m, where t is in s. What is the average vel
romanna [79]

Answer:

12m/s

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