CH_3 CH_2 Cl has two different types of hydrogen. On further chlorination they are being substituted by chlorine to give two isomeric dichlorides
The structures of the two chlorides are shown below.
Where Hb is replaced by Cl and Ha is replaced by Cl
Theses can include the power supply circuit a joule meter to measure the energy transferred which makes the calculations a lot easier.
Explanation:
P1V1 = nRT1
P2V2 = nRT2
Divide one by the other:
P1V1/P2V2 = nRT1/nRT2
From which:
P1V1/P2V2 = T1/T2
(Or P1V1 = P2V2 under isothermal conditions)
Inverting and isolating T2 (final temp)
(P2V2/P1V1)T1 = T2 (Temp in K).
Now P1/P2 = 1
V1/V2 = 1/2
T1 = 273 K, the initial temp.
Therefore, inserting these values into above:
2 x 273 K = T2 = 546 K, or 273 C.
Thus, increasing the temperature to 273 C from 0C doubles its volume, assuming ideal gas behaviour. This result could have been inferred from the fact that the the volume vs temperature line above the boiling temperature of the gas would theoretically have passed through the origin (0 K) which means that a doubling of temperature at any temperature above the bp of the gas, doubles the volume.
From the ideal gas equation:
V = nRT/P or at constant pressure:
V = kT where the constant k = nR/P. Therefore, theoretically, at 0 K the volume is zero. Of course, in practice that would not happen since a very small percentage of the volume would be taken up by the solidified gas.
Answer:
characteristic properties of an element are the defining properties of that element and it does not change with quantity of the element used.
Explanation:
the amount or the quantity of the element used does not affect the characteristic property of the element. it does not matter is the if the amount or the quantity of the element used in the reaction is large or the small the characteristic properties like boiling point, melting point, density, thermal conductivity, etc remain the same or remain constant.
