Brick is held at a position which is at height 2 m from the floor
Now it is released from rest and hit the floor after t = 4 s
Now the acceleration of the brick is given by



a)
Now in order to find the tension in the string
we can use Newton's law




part b)
Now for the pulley
moment of inertia= 
m = 30 kg
R = 2 m
I = 
I = 60 kg m^2
Now the angular speed just before brick collide with the floor
![w = \frac{v}{r}[\tex]here we have[tex]v = v_i + a* t](https://tex.z-dn.net/?f=w%20%3D%20%5Cfrac%7Bv%7D%7Br%7D%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3Ehere%20we%20have%3C%2Fp%3E%3Cp%3E%5Btex%5Dv%20%3D%20v_i%20%2B%20a%2A%20t)

v = 1 m/s
Now we will have
L = angular momentum = I w = 
L = 60 *
L = 30 kg m^2/s
Explanation:
Below is an attachment containing the solution.
centripetal acceleration is given by formula

given that


now we have




so the ratationa frequency is given by




This question can be solved using the concept of the composition of the vector.
(a) The magnitude of F is b "164.27 N".
(b) The angle of the vector from horizontal is " ".
(a)
From the composition of the rectangular components of a vector, we know that the magnitude of the resultant vector is given by the following formula:

where,
= x-component of the force = 122 N
= y-component of the force = 110 N
Therefore,

<u>F = 164.27 N</u>
(b)
The angle of the vector is given by the following formula:

<u>θ = 42.04°</u>
Learn more about the composition of vector here:
brainly.com/question/24313520?referrer=searchResults