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PolarNik [594]
3 years ago
14

Pls help me I will make you as Brainly

Physics
2 answers:
Helga [31]3 years ago
6 0

Answer:

D

Explanation:

Montano1993 [528]3 years ago
6 0

Answer:

b

Explanation:

You might be interested in
ustapha Jones is speeding on the interstate in his Ferrari at 231km/hr when he passes a police car at rest . If the cop accelera
Lena [83]

Answer:

461 km/h

Explanation:

In order to solve this problem we must first sketch a drawing of what the situation looks like so we can better visualize it. (See attached picture).

We have two situations there, the first one is Mustapha's car that is traveling at a constant speed of 231km/hr.

The second situation is the police that is accelerating from rest until he reaches Mustapha. (We are going to suppose the acceleration is constant and that he will not stop accelerating until he reaches Mustapha). He has an acceleration of 15m/s^{2}.

We want to find what the final velocity of the police is at the time he reaches Mustapha. From this we can imply that the displacement x will be the same for both particles.

So let's model the first situation.

The displacement of Mustapha can be found by using the following equation:

V_{M}=\frac{x}{t}

when solving the equation for the displacement x we get that it will be:

x=V_{M}t

Now let's model the displacement of the cop. Since the cop has a constant acceleration, we can model his displacement with the following formula.

x=V_{0}t+\frac{1}{2}at^{2}

Since the initial velocity of the cop is zero, we can get rid of that part of the equation leaving us with:

x=\frac{1}{2}at^{2}

We can now set both equations equal to each other so we get:

\frac{1}{2}at^{2}=V_{M}t

When solving this for t, we get that:

t=\frac{2V_{M}}{a}  (let's call this equation 1)

Now, we know the cop has constant acceleration, so we can model it with the following formula too:

a=\frac{V_{f}-V_{0}}{t}

since the initial velocity of the cop is zero, we can get rid of that here too, so we get the following formula:

a=\frac{V_{f}}{t}

when solving for the final velocity, we get that:

V_{f}=at  (let's call this equation 2)

when substituting equation 1 into equation 2 we get:

V_{f}=a(\frac{2V_{M}}{a})

we can now cancel a leaving us with:

V_{f}=2V_{M}

This tells us that the final velocity of the cop will not depend on his acceleration. (This is only if the acceleration is constant all the time) So we get that the final velocity of the cop is:

V_{f}=2(231km/hr)

so

V_{f}=461km/hr

which is our answer.

8 0
3 years ago
A 80 kg skier grips a moving rope that is powered by an engine and is pulled at constant speed to the top of a 25 degrees hill.
zloy xaker [14]

Answer:

P=28.085\,hp

Explanation:

Given that:

  • mass of 1 skier, m=80kg
  • inclination of hill, \theta=25^{\circ}
  • length of inclined slope, l=220m
  • time taken to reach the top of hill, t=2.3 min= 138 s
  • coefficient of friction, \mu=0.15

<em>Now, force normal to the inclined plane:</em>

F_N=m.g.cos\theta

F_N=80\times 9.8\times cos25^{\circ}

F_N=710.54\,N

<em>Frictional force:</em>

f=\mu.F_N

f=0.15\times 710.54

f=106.58\,N

<em>The component of weight along the inclined plane:</em>

W_l=m.g.sin\theta

W_l=80\times 9.8\times sin25^{\circ}

W_l=331.33\,N

<em>Now the total force required along the inclination to move at the top of hill:</em>

F=f+W_l

F=106.58+331.33

F=437.91\,N

<em>Hence the work done:</em>

W=F.l

W=437.91\times 220

W=96340.80\,J

<em>Now power:</em>

P=\frac{W}{t}

P=\frac{96340.80}{138}

P=698.12\,W

<u>So, power required for 30 such bodies:</u>

P=30\times 698.12

P=20943.65\,W

P=\frac{20943.65}{745.7}

P=28.085\,hp

8 0
3 years ago
Loops in a motor rotate because?​
ch4aika [34]

Answer:

Motors are the most common application of magnetic force on current-carrying wires. Motors have loops of wire in a magnetic field. When current is passed through the loops, the magnetic field exerts torque on the loops, which rotates a shaft. Electrical energy is converted to mechanical work in the process

Explanation:

hope that helps!

5 0
3 years ago
A decorative plastic film on a copper sphere of 10 mm diameter in an oven at 750C. Upon removal from the oven, the sphere is sub
AlladinOne [14]

Answer:

3.26 secs

Explanation:

Diameter of sphere ( D )= 10 mm

T1 = 75°C

P = 1 atm

T∞ = 23°C

T2 = 35°c

Velocity = 10 m/s

<u>Determine how long it will take to cool the sphere to 35°C</u>

<em>Using the properties of copper and air given in the question</em>

Nu = 2 + (Re)^0.8 (Pr)^0.33

hd / k = 2 + ( vd/v )^0.8 (Pr)^0.33

∴ h ≈  2594.7 W/m^2k

Given that :

(T2 - T∞) / ( T1 - T∞ )  = exp [ ( -hA / pv CP ) t ]  

( 35 - 23 ) / ( 75 - 23 ) = exp [  - 2594.7 * 6 * t / 8933 * 387 * 10 * 10^-3 ]

=  ln ( 12/52 ) = -1.466337069  =     - 0.45032919 *  t

∴ t ≈ 3.26 secs        ( -1.466337069 / -0.45032919 )

6 0
3 years ago
A person hits a 45-g golf ball. The ball comes down on a tree root and bounces
Verizon [17]

Answer:

Maximum height, h = 10 m          

Explanation:

It is given that,

Mass of golf ball, m = 45 g = 0.045 kg

The ball comes down on a tree root and bounces  straight up with an initial speed of 14.0 m/s.

We need to find the height the ball will rise  after the bounce. It is based on the conservation of energy such that,

\dfrac{1}{2}mv^2=mgh

h is maximum height raised by the ball

h=\dfrac{v^2}{2g}\\\\h=\dfrac{(14)^2}{2\times 9.8}\\\\h=10\ m

So, the ball will raised to a height of 10 meters.

5 0
3 years ago
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