We are given that the wavelength ʎ is from 400 nm to 700
nm. The formula for this is:
d sin a =m * ʎ
where,
d = slit separation = 1 mm / 750 lines = 1/750
a = angle
m = 1
ʎ = 400 nm to 700 nm = 0.0004 mm to 0.0007 mm
Rewriting the formula in terms of angle a:
a = sin^-1 (m ʎ / d)
when ʎ = 0.0004 mm
a = sin^-1 (0.0004 / (1/750))
a = 17.46°
when ʎ = 0.0007 mm
a = sin^-1 (0.0007 / (1/750))
a = 31.67°
Hence the range of angles is from 17.46° to 31.67<span>°.</span>
Answer:
a)= 0.025602u
b) = 23.848MeV
c) N = 1.546 × 10¹³
Explanation:
The reaction is
²₁H + ²₁H ⇄ ⁴₂H + Q
a) The mass difference is
Δm = 2m(²₁H) - m (⁴₂H)
= 2(2.014102u) - 4.002602u
= 0.025602u
b) Use the Einstein mass energy relation ship
The enegy release is the mass difference times 931.5MeV/U
E = (0.025602) (931.5)
= 23.848MeV
c)
the number of reaction need per seconds is
N = Q/E
= 59W/ 23.848MeV
N = 1.546 × 10¹³
Answer:
false
Explanation:
discovered colours of the rainbow
a) we can answer the first part of this by recognizing the player rises 0.76m, reaches the apex of motion, and then falls back to the ground we can ask how
long it takes to fall 0.13 m from rest: dist = 1/2 gt^2 or t=sqrt[2d/g] t=0.175
s this is the time to fall from the top; it would take the same time to travel
upward the final 0.13 m, so the total time spent in the upper 0.15 m is 2x0.175
= 0.35s
b) there are a couple of ways of finding thetime it takes to travel the bottom 0.13m first way: we can use d=1/2gt^2 twice
to solve this problem the time it takes to fall the final 0.13 m is: time it
takes to fall 0.76 m - time it takes to fall 0.63 m t = sqrt[2d/g] = 0.399 s to
fall 0.76 m, and this equation yields it takes 0.359 s to fall 0.63 m, so it
takes 0.04 s to fall the final 0.13 m. The total time spent in the lower 0.13 m
is then twice this, or 0.08s
