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Llana [10]
3 years ago
14

Cellular respiration uses glucose and oxygen, which have high levels of free energy, and releases carbon dioxide and water, whic

h have low levels of free energy. Is cellular respiration spontaneous or not? Is it exergonic or endergonic? What happens to the energy released from glucose?
Chemistry
2 answers:
Alja [10]3 years ago
4 0

Answer: Cellular respiration is spontaneous and exergonic. The energy released from the glucose is stored in ATP molelcules.

Explanation:

Spontaneous reactions have an increase in entropy (level of disorder) and a decrease in enthalpy (total energy). Cellular respiration goes from a more ordered state (one molecule of glucose) to a more disordered state (several molecules of CO2), and goes from a state with a lot of free energy to one with much less free energy. As a result, respiration is a spontaneous process.

As free energy from the glucose is released as ATP molecules during oxidation, the reaction is exergonic.

mars1129 [50]3 years ago
3 0

Answer:

Cellular respiration is spontaneous and exergonic. And the energy released during this process is used primarily for the formation of new chemical bonds (ATP)

Explanation:

In the catabolic reactions complex substances are transformed into simpler ones. When the molecules are degraded, they release the energy contained in the chemical bonds. This is the type of energy that is produced in cellular respiration.

Cellular respiration is an exergonic reaction, where part of the energy contained in the food molecules is used by the cell to synthesize ATP, which is a small molecule that powers reactions in the cell.  It is said that part of the energy is detected for synthesis, because much of the energy is dissipated as heat.

In chemistry, a spontaneous process is one that occurs without the external energy supply. And generally spontaneity is analyzed by Gibbs energy (G), which is a measure of the amount of usable energy. When ΔG <0 process is exergonic and will occur spontaneously directly to form more products.

When ΔG> 0 the process is endergonic and is not spontaneous in the direct sense. On the contrary, it will occur spontaneously in the opposite direction to produce more reagents.

When ΔG = 0, the system is in equilibrium and the concentrations of products and reagents will remain constant.

The general reaction of the analyzed process can write as follows:

C_{6} H_{12}O_{6}  + 6O_{2} ⇒ 6 CO_{2} + 6H_{2} O

ΔG=-686 \frac{kcal}{mol}

As you can see, G is less than zero. It was also mentioned that cellular respiration is an exergonic reaction. Then it can be said that it is a spontaneous reaction.

In summary, cellular respiration is spontaneous and exergonic. And the energy released during this process is used primarily for the formation of new chemical bonds (ATP)

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Given the partial equation:
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Answer : The balanced chemical equation in acidic medium will be,

IO_3^-(aq)+2Sn^{2+}(aq)+6H^+(aq)\rightarrow I^-(aq)+2Sn^{4+}(aq)+3H_2O(l)

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Rules for the balanced chemical equation in acidic solution are :

First we have to write into the two half-reactions.

Now balance the main atoms in the reaction.

Now balance the hydrogen and oxygen atoms on both the sides of the reaction.

If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the less number of oxygen are present.

If the hydrogen atoms are not balanced on both the sides then adding hydrogen ion (H^+) at that side where the less number of hydrogen are present.

Now balance the charge.

The given chemical reaction is,

IO_3^-(aq)+Sn^{2+}(aq)\rightarrow I^-(aq)+Sn^{4+}(aq)

The oxidation-reduction half reaction will be :

Oxidation : Sn^{2+}\rightarrow Sn^{4+}

Reduction : IO_3^-\rightarrow I^-

First balance the main element in the reaction.

Oxidation : Sn^{2+}\rightarrow Sn^{4+}

Reduction : IO_3^-\rightarrow I^-

Now balance oxygen atom on both side.

Oxidation : Sn^{2+}\rightarrow Sn^{4+}

Reduction : IO_3^-\rightarrow I^-+3H_2O

Now balance hydrogen atom on both side.

Oxidation : Sn^{2+}\rightarrow Sn^{4+}

Reduction : IO_3^-+6H^+\rightarrow I^-+3H_2O

Now balance the charge.

Oxidation : Sn^{2+}\rightarrow Sn^{4+}+2e^-

Reduction : IO_3^-+6H^++4e^-\rightarrow I^-+3H_2O

The charges are not balanced on both side of the reaction. Thus, we are multiplying oxidation reaction by 2 and the adding both equation, we get the balanced redox reaction.

Oxidation : 2Sn^{2+}\rightarrow 2Sn^{4+}+4e^-

Reduction : IO_3^-+6H^++4e^-\rightarrow I^-+3H_2O

The balanced chemical equation in acidic medium will be,

IO_3^-(aq)+2Sn^{2+}(aq)+6H^+(aq)\rightarrow I^-(aq)+2Sn^{4+}(aq)+3H_2O(l)

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3 years ago
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