Answer:
Δx ≥ 1.22 *10^-10m
Explanation:
<u>Step 1:</u> Data given
The E. coli bacterial cell has a mass of 1.80 fg ( = 1.80 * 10^-15 grams = 1.80 * 10^-18 kg)
Velocity of v = 8.00 μm/s (= 8.00 * 10^-6 m/s)
Uncertainty in the velocity = 3.00 %
E. coli bacterial cells are around 1 μm = 10^−6 m in length
<u>Step 2:</u> Calculate uncertainty in velocity
Δv = 0.03 * 8*10^-6 m/s =2.4 * 10^-7 m/s
<u>Step 3:</u> Calculate the uncertainty of the position of the bacterium
According to Heisenberg uncertainty principle,
Δx *Δp ≥ h/4π
Δx *mΔv ≥ h/4π
with Δx = TO BE DETERMINED
with m = 1.8 *10^-18 kg
with Δv = 2.4*10^-7
with h = constant of planck = 6.626 *10^-34
Δx ≥ 6.626*10^-34 / (4π*(1.8*10^-18)(2.4*10^-7))
Δx ≥ 1.22 *10^-10m
Answer: 50. 4g
Explanation:
First calculate number of moles of aluminium in 38.8g
Moles = 38.8g/ 26.982mol/g
= 1.44mol
By looking at the balance equation you can see that 4 moles of aluminium produce 2 moles of aluminium oxide.
4 = 2
1.4 = x
Find the value of x
x= (1.4×2)/4= 0.72 mol
0.72 moles of aluminium oxide are produced from 38.8g of aluminium
Now find the mass of aluminium produced.
Mass = moles × molar mass
= 0.72mol × 69.93 mol/g
= 50.4g
Answer:
ik ppl sy no links but https://courses.lumenlearning.com/cheminter/chapter/the-ph-scale/
Explanation: it should help you
