the answer is Cl2Mn . The 2 is below .
Determine the mass of each of the following amounts. a. 1.366 mol of
NH3
, b. 0.120 mol of glucose,
C6H12O6
, c. 6.94 mol barium chloride,
BaCl2
, d. 0.005 mol of propane,
C3H8
Answer:
The molarity of the solution is 0,99M
Explanation:
We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)
Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g
58, 5 g-----1 mol NaCl
145 g ---------x= (145 g x 1 mol NaCl)/58, 5 g= 2,48 mol NaCl
2,5 L solution------ 2, 48 mol NaCl
1 L solution------x= (1 L solutionx 2, 48 mol NaCl)/2,5L solution
x=0,99 mol NaCl---> The solution is 0,99 molar (0,99 M)
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