Answer:
0.0933 moles/Litre
Explanation:
We assume that the number of moles of N- used is equal to the number of moles of Nitrogen containing compounds that are generated due to the fact that the nitrogen containing compound that are produced contain only one nitrogen in each atom. As such, finding the amount of nitrogen used up explains the amount of compound formed. This can be expressed as follows:
Energy cost =
Given that:
Energy = 100 W for 60 minutes
100 W = 100 J/s
= 100 J/s × (60 × 60) seconds
= 3.6 × 10⁵ J
Let now convert 3.6 × 10⁵ J to eV; we have:
= ( 3.6 × 10⁵ × 6.242 × 10¹⁸ )eV
= 2.247 × 10²⁴ eV
So, number of N-atom used up to form compounds will now be:
= 2.247 × 10²⁴ eV ×
= 1.123 × 10²³ N-atom
To moles; we have:
=
= 0.186 moles
However, we are expected to leave our answer in concentration (i.e in moles/L)
since we are given 2L
So; 0.186 moles ⇒
= 0.0933 moles/Litre
In a model, the particles are not the actual size. They are just representing the gas particles. In a gas, the particles are smaller and in their own material
Explanation:
For the given reaction:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
where x and y are order wrt to and
According to collision theory , the molecules must collide for a reaction to take place. According to collision theory , the rate of a reaction is proportional to rate of collision of reactants.
Thus with an increase in concentration of reactants , the rate of reaction also increases. This is because if the concentration of reactants increases , the chances of collision between molecules also increases and thus more products wil be formed which in turn increases the rate of reaction.
Answer:
1550.8
Explanation:
This is the ideal gas equation:
PV=nRT
We can rearrange the ideal gas equation to solve for the pressure of the nitrogen gas.
P=nRT/ V
We can find the pressure of the nitrogen gas by plugging in the values for the moles of gas, temperature, and volume. Since we want the pressure in units of Torr we use the R value62.36358L Torr K−1 mol-1
P=nRT/ V
(0.316 mol )(62.36358 L*Torr/K*mol)(315 K) / 4.00 L =1550 Torr
The correct answer is 1550
Answer:
Formula mass = 58.09 g
Explanation:
Formula mass of a given molecule is defined as the sum of atomic masses of elements forming the empirical formula of that molecule.
In order to calculate the formula mass of propanol, following data is required;
Empirical Formula of Propanol:
The empirical formula of Propanol is C₃H₆O (also the molecular formula) as it is the lowest possible atomic ratio of the given elements.
Atomic Masses of Elements:
Carbon = 12.01 g/mol
Hydrogen = 1.01 g/mol
Oxygen = 16.00 g/mol
Hence,
Formula mass = (At. mass of C)₃ + (At. mass of H)₆ + (At. mass of O)
Formula mass = (12.01)₃ + (1.01)₆ + (16.00)
Formula mass = 36.03 + 6.06 + 16.00
Formula mass = 58.09 g