We are given that a 500 kg object is hanging from a spring. To determine the amount the spring is stretched we will use Hook's law, which states the following:

Where:

Since the object is hanging the only force acting on the spring is the weight of the object. The weight of the object is:

Where:

Plugging in the values we get:

Solving the operations:

Now we solve for "x" from Hook's law by dividing both sides by "k":

Now we plug in the known values:

Solving the operations:

Therefore, the spring is stretched by 5.4 meters.
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Answer:
179.655m
Explanation:
Given
Maximum speed of the arrow v = 60m/s
Time taken to hit the top of the cliff t = 7.0s
Required
Height of the cliff H
Using the equation of motion
H = vt + 1/2gt²
Substitute into the formula:
H = 60(7) + 1/2 (-9.81)(7²) (g is negative due to upward motion of the arrow)
H = 420-4.905(49)
H = 420-240.345
H = 179.655m
Hence the cliff is 179.655m high
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