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algol13
3 years ago
14

A 2.0 m tall person is standing in front of a flat vertical mirror. What minimum height must the mirror have if the person is to

see her entire body, from the top of her head to her feet?
Physics
1 answer:
dangina [55]3 years ago
7 0

Answer:

100cm

Explanation:

Since the eyes are 6 cm below the top of her head, the point of incidence of the ray must be

200cm-3cm=197cm

Since the eyes are 194 cm from her feet, the point of incidence of this ray must be

194cm/2=97cm

So the lower edge of the mirror must be 97 cm from the ground and the vertical dimension of the mirror must be 197 cm - 97 cm = 100 cm, which is half the height of the person.

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A river flows with a speed of 0.600 m/s. A student first swims upriver 0.500 km, then turns around and returns to his starting p
DerKrebs [107]

Answer:

a) 1111.0 seconds

b) 833.3 s

c) Because of proportions

Explanation:

a) Total time of round trip is the sum of time upriver and time downriver

t_{total}=t_{up}+t_{down}

Time upriver is calculated with the net speed of student and 0.500 km:

t_{up}=\frac{d_{istance}}{|v_{swimmer}|} ;\\v_{swimmer}=v_{relative to river}+v_{river}=-1.2+0.6=-0.6 m/s\\t_{up}=\frac{500 m}{0.6 m/s}=833.3 s

(Becareful with units 0.5 km= 500m) Similarly of downriver:

t_{down}=\frac{d_{istance}}{|v_{swimmer}|} ;\\v_{swimmer}=1.2+0.6=1.8 m/s\\t_{down}=\frac{500 m}{1.8 m/s}=277.7 s

So the sum is:

t_{total}=1111.0s

b) Still water does not affect student speed, so total time would be simply:

t_{total}=\frac{1000 m}{1.2 m/s}=833.3 s

c) For the upriver trip, student moved half the distance in half speed of the calculation in b), so it kept the same ratio and therefore, same time. So the aditional time is actually the downriver.  

6 0
2 years ago
Does sand stay sand forever?
Gemiola [76]

Answer:

No sand doesn't stay sand forever.

Explanation:

  • We may have a thought that the sand we see on the beach areas are always the same one for eternal, but it is not true.
  • Due to different activities like beach nourishment, sand replenishment etc. the sand in the beach areas are changed and replaced.
  • If the sand remained there for long time, it also affects the sand eating organisms and plants.
3 0
3 years ago
A 3 kg penguin is pushed by his penguin friends who give him an initial speed vo at the top of a 30 m hill. The penguin is hopin
Strike441 [17]

Answer:

This question can be answered by using conversation of energy.

K_1 + U_1 = K_2 + U_2

\frac{1}{2}mv_{0}^2 + mgh_1 = 0 + mgh_2

\frac{1}{2}(3)v_0^2 + (3)(9.8)(30) = (3)(9.8)(45)\\\frac{1}{2}(3)v_0^2 = 441\\v_0^2 = 294\\v_0 = 17.14 m/s

Explanation:

Note that we take K_2 = 0 because we are looking for the minimum initial speed for the penguin to reach the top of the second hill. Any other speed more than this will already be enough for him.

7 0
3 years ago
If an object were released in space far away from planted or stars and given an initial momentum, describe what would happen to
mamaluj [8]
Strange as it may seem, the object would keep moving, in a straight line and at the same speed, until it came near another object. Its momentum and kinetic energy would never change. It might continue like that for a billion years or more.

Have a look at Newton's first law of motion.
7 0
3 years ago
Read 2 more answers
7) T F If two forces of equal magnitude act on an object that is hinged at a pivot, the force acting farther from the pivot must
saul85 [17]

Answer:

False

Explanation:

The torque exerted by a force is given by:

\tau=Fd sin \theta

where

F is the magnitude of the force

d is the distance between the point of application of the force and the pivot

\theta is the angle between the directions of F and d

We see that the magnitude of the torque depends on 3 factors. In this problem, we have 2 forces of equal magnitude (so, equal F). Moreover, one of the forces (let's call it force 1) acts farther from the pivot than force 2, so we have

d_1 > d_2

However, this does not mean that force 1 produces a greater torque. In fact, it also depends on the angle at which the force is applied. For instance, if the first force is applied parallel to d, then we have

\theta_1 =0\\sin \theta=0

and the torque produced by this force would be zero.

So, the statement is false.

4 0
3 years ago
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